The range of frequencies of visible light in a vacuum is mathematically given as
Fmin=4.19*10^14Hz to Fmax=1*10^15Hz
<h3>What is the range of frequencies of visible light in a vacuum?</h3>
Question Parameters:
The wavelengths of visible light vary from about 300 nm to 700 nm.
Generally, the equation for the frequency is mathematically given as
F=C/\lambda
Therefore
For Fmax

Fmax=1*10^15Hz
Where

Fmin=4.19*10^14Hz
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Well, the answer to this question is D) 10 m/s^2 in the direction of the meteoroids motion.
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Also, can you please mark my answer as the brainliest answer?
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Answer:
a) 147.95 Mpc
Explanation:
Using Hubble's formula

where;
v = radical velocity
= Hubble's constant
d = distance
Given that:
The average radial velocity of galaxies in the Hercules cluster v = 10,800 km/s
Also using
= 73 km/s/ Mpc ; we make distance d the subject of the formula:
Then distance d can be written as:


d = 147.95 Mpc
b)
Now, if the Hubble constant had a smaller value, then for a given velocity the distance to the galaxy will increase because distance d is inversely proportional to
i.e
d ∝ 
Answer:
I think it's D
Explanation:
because I have seen the tracks of the tires
They all move through empty space at the speed of light