<h3><u>Answer;</u></h3>
C. 12 units
<h3><u>Explanation;</u></h3>
- If the strength of the magnetic field at B is 3 units, the strength of the magnetic field at A is 12 units
- Magnetic field strength is one of two ways that the intensity of a magnetic field can be expressed.
- <em><u>The strength of the field is inversely proportional to the square of the distance from the source. This means that If the distance between two points in magnetic filed is doubled the magnetic force between them will fall to a quarter of the initial value. </u></em>
- <em><u>On the other hand, if the distance between two magnets is halved the magnetic force between them will increase to four times the initial value.</u></em>
<span>♦The gas may become a liquid as it loses energy♦</span>
Answer:
Ferromagnetism, physical phenomenon in which certain electrically uncharged materials strongly attract others. Two materials found in nature, lodestone (or magnetite, an oxide of iron, Fe3O4) and iron, have the ability to acquire such attractive powers, and they are often called natural ferromagnets.
Hope this help :)
Answer:
![a=368.97\ m/s^2](https://tex.z-dn.net/?f=a%3D368.97%5C%20m%2Fs%5E2)
Explanation:
Given that,
Initial angular velocity, ![\omega=0](https://tex.z-dn.net/?f=%5Comega%3D0)
Acceleration of the wheel, ![\alpha =7\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D7%5C%20rad%2Fs%5E2)
Rotation, ![\theta=14\ rotation=14\times 2\pi =87.96\ rad](https://tex.z-dn.net/?f=%5Ctheta%3D14%5C%20rotation%3D14%5Ctimes%202%5Cpi%20%3D87.96%5C%20rad)
Let t is the time. Using second equation of kinematics can be calculated using time.
![\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s](https://tex.z-dn.net/?f=%5Ctheta%3D%5Comega_it%2B%5Cdfrac%7B1%7D%7B2%7D%5Calpha%20t%5E2%5C%5C%5C%5Ct%3D%5Csqrt%7B%5Cdfrac%7B2%5Ctheta%7D%7B%5Calpha%20%7D%7D%20%5C%5C%5C%5Ct%3D%5Csqrt%7B%5Cdfrac%7B2%5Ctimes%2087.96%7D%7B7%7D%7D%20%5C%5C%5C%5Ct%3D5.01%5C%20s)
Let
is the final angular velocity and a is the radial component of acceleration.
![\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s](https://tex.z-dn.net/?f=%5Comega_f%3D%5Comega_i%2B%5Calpha%20t%5C%5C%5C%5C%5Comega_f%3D0%2B7%5Ctimes%205.01%5C%5C%5C%5C%5Comega_f%3D35.07%5C%20rad%2Fs)
Radial component of acceleration,
![a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Comega_f%5E2r%5C%5C%5C%5Ca%3D%2835.07%29%5E2%5Ctimes%200.3%5C%5C%5C%5Ca%3D368.97%5C%20m%2Fs%5E2)
So, the required acceleration on the edge of the wheel is
.
Solid at room temperature