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3 years ago

Write a system of two equations.

1 answer:

8 0

A system of linear equation consists of two or more linear equations with the two or more same variables. Such equations are called system of equations (or) simultaneous equations (or) a pair of equations.

Example:

x + y = 5 is one linear equation.

2x – y = 4 is another linear equation.

But x + y = 5, 2x – y = 4 together they form system of linear equation.

The solution to a system of linear equations in two variables is any ordered pair that satisfies each equation independently.

You might be interested in

Find me equation of the circle with Center at ( 3, - 2) and radius of 3

blondinia [14]

The equation of a circle with center $(x_0,y_0)$ and radius $r$ is

$(x-x_0)^2+(y-y_0)^2=r^2$

In your case,

$x_0=3,\quad y_0=-2,\quad r=3$

Plug these values into the generic formula and you'll get your equation.

5 0

3 years ago

Solve for x<br> 5x-1= 2x+5

vladimir1956 [14]

5x = 2x + 5 + 1

5x = 2x + 6

5x - 2x = 6

3x = 6

x = 6/3

x=2

3 0

3 years ago

Read 2 more answers

How is the graph of y =(x-1)2 - 3 transformed to produce the graph of y = 5(X+4)??

lina2011 [118]

Answer:

<h2>The graph is translated left 5 units, compressed vertically by a factor of 5, and translated up 3 units.</h2>

Step-by-step explanation:

The initial function is

$y=(x-1)^{2} -3$

The transformed function is

$y=5(x+4)^{2}$

Notice that the first function represents a parabola with vertex at (1, -3), and the secong function represents a parabola with vertex at (-4, 0). That means the function was shifted three units up and 5 units to the left. Additionally, the function was compressed by a scale factor of 5, because that's the coffecient of the quadratic term.

Therefore, the right answer is the first choice.

6 0

3 years ago

PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((

shutvik [7]

Okay..it goes -75, 0, 25, and then 50.

Hope this helps.

7 0

3 years ago

Read 2 more answers

Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....

lina2011 [118]

Answer:Answer:

$\sum\left {{7} \atop {1}} \right -n(3+n)$

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as $S_n = \frac{n}{2}[2a+(n-1)d]$

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

$S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70$

The sum of the nth term of the sequence will be;

$S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)$

The sigma notation will be expressed as $\sum\left {{7} \atop {1}} \right -n(3+n)$ . <em>The limit ranges from 1 to 7 since we are to find the sum of the first seven terms of the series.</em>

3 0

3 years ago