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katrin [286]
3 years ago
14

A sandbag is released from a hot air balloon that is 400 ft above the ground. Using the falling object model, h = −16t^2 + s, wh

ere h = height in feet, t = time in seconds, and s = initial height in feet, how long will it take for the sandbag to hit the ground? A. 4 seconds B. 5 seconds C. 20 seconds D. 25 seconds

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

  B. 5 seconds

Step-by-step explanation:

A graphing calculator shows the answer easily.

__

h(t) = 0 = -16t^2 +400

t = √(400/16) = 5

It will take 5 seconds for the sandbag to hit the ground.

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Diego is solving this system of equations:
USPshnik [31]

The solutions of the equations are x = 1 and y = 2

The system of equations are

4x + 3y = 10

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Here we have to use the elimination method. Eliminate the x term and find the value of y term

Add both equation

3y + 5y = 10 +6

Add the like terms

8y = 16

y = 16 / 8

Divide  the terms

y = 2

Substitute the value of x in the first equation

4x + 3y = 10

4x + 3×2 =  10

Multiply the terms

4x + 6  = 10

4x = 10 - 6

4x = 4

x = 4 / 4

Divide the terms

x = 1

Hence, the solutions of the equations are x = 1 and y = 2

Learn more about elimination method here

brainly.com/question/14619835

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7 0
1 year ago
Solve for x in the triangle.Round your answer to the nearest tenth.
enyata [817]

sin = opposite/hypotenuse

sin 40° = 12/x

Cross multiply.

0.64278760968x = 12

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5 0
3 years ago
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*Awarding Brainliest!*
Alex73 [517]

Answer:

Step-by-step explanation:

The angles labeled 4y - 8 and 79 + y are called vertical angles, and definition, vertical angles are congruent.  That means algebraically, that

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3 years ago
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Jeremy claims that if a linear function has a slope of the same steepness and the same y-intercept as the linear function in the
4vir4ik [10]

Answer: It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.

Step-by-step explanation:

Let us consider the general linear equation

Y = MX + C

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-1 = 1/2(0) + C

C = -1

The equations for the coordinate is therefore

Y = 1/2X - 1

Let's check the equations one after the other

y = negative one-half x minus 1

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Y = -1/2X + 1

y = one-half x minus 1

Y = 1/2X - 1

y = one-half x + 1

Y = 1/2X + 1

It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.

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3 years ago
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Rzqust [24]

Answer:

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