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hammer [34]
3 years ago
11

What is the equation of a line that passes through points (0, 4) and (-4, -8)?

Mathematics
1 answer:
vladimir2022 [97]3 years ago
7 0

Answer:

y = 3x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (- 4, - 8)

m = \frac{-8-4}{-4-0} = \frac{-12}{-4} = 3

Note the line passes through the y- axis at (0, 4) ⇒ c = 4

y = 3x + 4 ← equation of line

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Lostsunrise [7]

Answer:

4.25

Step-by-step explanation: 12q - 9 ) + ( 8q + 14 ) = 90

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Subtract 5 from both sides: 20q = 85

Divide both sides by 20: q=4*(1/4)

So your angle is 4(1/4) or 4.25 degrees

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