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geniusboy [140]
3 years ago
8

A solution is prepared by dissolving 96.4 g of RbI in enough water to form 865 mL of solution. Calculate the mass % of the solut

ion if the density of the solution is 1.06 g/mL.
Chemistry
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

The mass % of the solution is 10.51%.

Explanation:

Mass of solute i.e. RbI = 96.4 g

Volume of the solution = 865 mL

Mass of the solution = m

Density of the solution = d = 1.06 g/mL

m=1.06 g/mL\times 865 mL=916.9 g

The mass % of the solution:

=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

=\frac{96.4 g}{916.9 g}\times 100=10.51\%

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Döbereiner grouped the known elements into <em>triads</em> (sets of three) so that

• The <em>atomic mass of the middle element</em> was approximately the average    of the other two

• The <em>chemical properties of the middle element</em> were between those of the other two

• The <em>physical properties of the middle element</em> were between those of the other two

One example of a triad is Li – Na – K.

(a) Atomic mass of Na = 23.0 u

       Average atomic mass of Li and K = (6.9 u + 39.1 u)/2 = 46.0 u/2 = 23.0 u

(b) Li reacts slowly with water. Na reacts rapidly. Potassium reacts violently.

(c) Melting point of Na = 371 °C.

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The end of one bar magnet is placed near the end of another bar magnet. The two ends seem to push each other apart. Which of the
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Answer:

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Magnets are composed of a north pole and a south pole. If two like poles of a magnetic are placed near each other, the two ends seem to push apart.

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Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.
zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation  </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:  

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So that the three laws can be combined into a single gas equation, the ideal gas equation  

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

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P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

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T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol

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