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Goshia [24]
2 years ago
7

3. Move the slider on the burette to the top to add about 25 mL of NaOH to the flask. What

Chemistry
1 answer:
UNO [17]2 years ago
6 0

Answer:

When you move the burette slider to the top of a flask and add about 25 mL of NaOH to the flask, you will cause a concentration of OH- molecules. This will make the solution become a basic solution and make the litmus paper blue.

Explanation:

After reading your question, we can see that you are carrying out a test to discover the nature of the pH of a solution. This type of test uses litmus paper, which is an indicator of the presence of acids and bases, being able to determine the pH of a solution. This paper is soaked in organic ink and when placed in an acidic solution, it is red in color. However, when placed in a basic solution it has a blue color.

An acidic solution is one that has a high concentration of H+ atoms and has the ability to donate electrons. The basic solution, on the other hand, has a high concentration of OH- and has the capacity to receive electrons.

When you move the burette slider to the top of a flask and add about 25 mL of NaOH to the flask, you will cause a concentration of OH- molecules. This will make the solution become a basic solution and make the litmus paper blue, that is, the solution has the basic pH.

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There are three isotopes of X element (X):
Nutka1998 [239]

Answer:

Average atomic mass = 17.5 amu.

Explanation:

Given data:

X-17 isotope = atomic mass17.2 amu, abundance:78.99%

X-18isotope =  atomic mass 18.1 amu, abundance 10.00%

X-19isotope = atomic mass:19.1 amu, abundance: 11.01%

Average atomic mass of X = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass)  / 100

Average atomic mass  = (78.99×17.2)+(10.00×18.1) +(11.01+ 19.1) /100

Average atomic mass =  1358.628 + 181 +210.291 / 100

Average atomic mass  = 1749.919 / 100

Average atomic mass = 17.5 amu.

8 0
3 years ago
An ideal gas differs from a real gas in that the molecules of an ideal gas __________. a have a molecular weight of zero b have
Rasek [7]
An ideal gas differs from a real gas in that the molecules of an ideal gas have no attraction for one another. 
An ideal gas is defined as one in which collisions between atoms or molecules are perfectly elastic and in which there are no inter-molecular attractive forces. A real gas on the other hand is a gas that does not behave as an ideal gas due to interactions between gas molecules. Particles in a real gas have a real volume since real gases are made up of molecules or atoms that typically take up some space even though they are extremely small. 
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3 years ago
The adult blue whale has a lung capacity 5.0\times10^3 5.0 Ã 10 3 l. calculate the mass of air (assume an average molar mass of
Andre45 [30]
For this item, we need to assume that air behaves like that of an ideal gas. Ideal gases follow the ideal gas law which can be written as follow,
    PV = nRT
where P is the pressure, 
V is the volume,
 n is the number of mols,
R is the universal gas constant, and 
T is temperature

In this item, we are to determine first the number of moles, n. We derive the equation,
       n = PV /RT
Substitute the given values,

    n = (1 atm)(5 x 10³ L) / (0.0821 L.atm/mol.K)(0 + 273.15)
    n = 223.08 mols

From the given molar mass, we calculate for the mass of air.
   m = (223.08 mols)(28.98 g/mol) = 6464.9 g

<em>ANSWER: 6464.9 g</em>
8 0
3 years ago
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Answer:

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Explanation:

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Answer:

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