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Karo-lina-s [1.5K]
3 years ago
12

What's the difference between anxiety and depression

Physics
2 answers:
Sedbober [7]3 years ago
7 0
Anxiety is when you have an overwhelming feeling of nervousness or worry. Depression is when sadness takes control of your mind and your body.
Nadya [2.5K]3 years ago
4 0

Answer:

Anxiety is an constance feeling when you  worry about something too much. this can get out of hand and a therapy is needed.

whereas depression is sadness and boredom that can mess with your feelings and confuse you. this also can get out of help as people with depression want and will stay in the house, this can upset your mental health, when this happen, it takes a year or more to retain you back to your self.

hope this helps

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The Earth's _____
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Answer:

rotation

Explanation:

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9. If everything in the universe – including atoms and particles stop moving, does time stop? Or does time continue even if ever
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Time stops everything is made out of atoms so if atoms freeze everything freezes
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You are measuring the mass of different chemicals to get ready to conduct an experiment.
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B) grams

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A 2.50-m segment of wire carries 1000 A current and feels a 4.00-N repulsive force from a parallel wire 5.00 cm away. What is th
Stolb23 [73]

Answer:

The current is  I_b  =  400 \ A

Explanation:

From the question we are told that

    The  length of the segment is  l  =  2.50  \  m

     The current is  I_a  =  1000 \ A

     The force felt is  F  =  4.0 \  N

        The distance of the second wire is  d =  5.0 \ cm  = 0.05 \  m

Generally the current on the second wire is mathematically represented as

        I_b  =  \frac{2 \pi * r * F }{ l *  \mu_o  *  I_a }

Here  \mu_o is the permeability of free space with value  \mu_o =  4 \pi * 10^{-7} \ N/A^2

=>      I_b  =  \frac{2 * 3.142  *  0.05 *  4 }{ 2.50  *  4\pi *10^{-7}  * 1000 }

=>      I_b  =  400 \ A

4 0
3 years ago
The top of the pool table is 0.810 m from the floor. the placement of the tape is such that 0 m is aligned with the edge of the
8090 [49]
Compute first for the vertical motion, the formula is:

y = gt²/2 

0.810 m = (9.81 m/s²)(t)²/2 

t = 0.4064 s 


whereas the horizontal motion is computed by: 

x = (vx)t 

4.65 m = (vx)(0.4064 s) 

4.65 m/ 0.4064s = (vx)

(vx) = 11.44 m / s
So look for the final vertical speed. 

(vy) = gt 

(vy) = (9.81 m/s²)(0.4064 s) 

(vy) = 3.99 m/s 


speed with which it hit the ground: 

v = sqrt[(vx)² + (vy)²] 

v = sqrt[(11.44 m/s)² + (3.99 m/s)²] 

v = 12.12 m / s
6 0
3 years ago
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