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d1i1m1o1n [39]
3 years ago
10

José and Laurel measured the length of a stick's shadow during the day. Without knowing the length of the stick, which of their

measurements would you ask José and Laurel to examine more closely? A. 50 cm at 6:00 a.m. B. 75 cm at 12:30 p.m. C. 42 cm at 5:45 p.m. D. 55 cm at 7:15 p.m. dont speak spanish answer with english plz???
Physics
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

Option B.

Explanation:

Assuming the stick is in vertical position, its shadow depends on two factors: its length and the angle between the sun rays and the stick. When the angle is bigger, the lenght of the shadow increases, and vice versa. So, when the sun rays are parallel to the stick, the shadow may be small. Since they are nearly perpendicular to the Earth's surface at 12 o'clock, the shadow of the stick at that time should be minimal. It means that the measured shadow of 75 cm at 12:30 p.m. is almost impossible (Option B).

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What happens to the water after it goes<br> down the drain?
valentina_108 [34]

Answer:

, it flows through your community's sanitary sewer system to a wastewater treatment facility.

6 0
3 years ago
a paper airplane gliding down towards the ground will experience the force of air resistance pushing up. the weight of the paper
Oduvanchick [21]

The net force acting on the airplane is 25N.

Forces acting on the paper airplane when it is in the air:

  • The forward force generated by the engine, propeller, or rotor is called thrust. It resists or defeats the drag force. It operates generally perpendicular to the longitudinal axis. However, as will be discussed later, this is not always the case.
  • Drag is an airflow disruption generated by the wing, rotor, fuselage, and other projecting surfaces that causes a backward, decelerating force. Drag acts backward and perpendicular to the relative wind, opposing thrust.
  • Weight is the total load carried by airplane, including the weight of the crew, fuel, and any cargo or baggage. Due to the influence of gravity, weight pulls the airplane downward.
  • Lift—acts perpendicular to the flight path through the center of lift and opposes the weight's downward force. It is produced by the air's dynamic influence on the airfoil.

Given.

Weight of the paper airplane, F1 = 16N

The force of air resistance, F2 = 9N

Net force = F1 + F2

Net force = 25N

Thus, the net force acting on the airplane is 25N.

Learn more about the net force here:

brainly.com/question/18109210

#SPJ1

3 0
1 year ago
The answer and how to do it?? Thanks
denis-greek [22]

Answer:

14 m/s²

Explanation:

Start with Newton's 2nd law: Fnet=ma, with F being force, m being mass, and a being acceleration. The applied forces on the left and right side of the block are equivalent, so they cancel out and are negligible. That way, you only have to worry about the y direction. Don't forget the force that gravity has the object. It appears to me that the object is falling, so there would be an additional force from going down from weight of the object. Weight is gravity (can be rounded to 10) x mass. Substitute 4N+weight in for Fnet and 1kg in for m.

(4N + 10 x 1kg)=(1kg)a

14/1=14, so the acceleration is 14 m/s²

4 0
3 years ago
Who would hire a forensic toxicologist
romanna [79]

Answer:

Scientists or doctors

Explanation:

5 0
3 years ago
Read 2 more answers
The mass of the Mars is about 0.11 the mass of the earth, its radius is 0.53 that of the earth, and the acceleration due to grav
pishuonlain [190]

Answer:

3.8377m/s^2

Explanation:

The force due to gravity on earth's surface on mass m is:

F=GMm/R^2

Where,

F = GMm/R2

F = Gravitational Force

G = Gravitational Constant

M = Earth's Mass

m = mass of body

R = Earth's radius

The acceleration is F/m:

g=F/m=GM/R^2

For a planet with 0.11M and 0.53R:

a=G(0.11M)/(0.53R)^2\\=0.3915g\ \ \ \ \ \ \g=9.8m/s^2\\=0.3915\times9.8m/s^2\\\\=3.8377m/s^2

Hence gravity on Mar's surface is 3.8377m/s^2

4 0
3 years ago
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