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2 years ago

Find the next three numbers in the pattern. 5, 10, 20, 40, Would I add or multiply?

Mathematics

2 answers:

Gnom [1K]2 years ago

7 0

Step-by-step explanation:

The rule of the pattern follows that the next number can be found by multiplying the preceeding number by the constant 2

so to find the next three numbers,multiply the preceeding number by 2 thus 5,10,20,40,80(thus 40×2),160(thus 80×2),320(thus 160×2)

gavmur [86]2 years ago

4 0

Answer:

firstly you know the term of multiplication

like 5*2=10 ,10*2=20, 20*2 =40 and 40*2 =80

and last three numbers are 80, 160,320

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Find equation of a line through (1,4) and (1,6)

Elena L [17]

Notice the picture below

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3 years ago

2. Write the following in order from least<br> to greatest:<br><br> 0.7, 0.84, 4/5, 82%, 71/100

lutik1710 [3]

Answer:

0.7, 71/100, 4/5, 82%, 0.84

4 0

3 years ago

Read 2 more answers

Marking as brainliest!!!!

7nadin3 [17]

Answer:

The answer to your question is: Letter A

Step-by-step explanation:

Data

M (-6, 7)

E (4, 11)

r = 1 / 3

Formula

$x = \frac{x1 + rx2}{1 + r}$

$y = \frac{y1 + ry2}{1 + r}$

x = $\frac{-6 + (1/3)(11)}{(4/3)} = \frac{-6 + (4/3)}{(4/3)} = \frac{-18 + 4}{4} = \frac{-14}{4} = \frac{-7}{2}$

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5 0

3 years ago

The length of a rectangular rug is 4 feet more than the width. If the area of the rug is 252 square feet, find the dimensions of

Allushta [10]

4 x ? = 252

Do the opposite of multiplication.

252 ÷ 4 = ?

? = 63.

Hope this Helps! :)

6 0

4 years ago

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

3 years ago