1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lemur [1.5K]
3 years ago
7

A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio

n force be required? If so, how much and in what direction?
Physics
1 answer:
Mariulka [41]3 years ago
5 0

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

You might be interested in
A force on a toy airplane exerted a work of 100 J. What was the change in the kinetic energy?
klemol [59]

Answer:

it probs gos fast then it was it would be easy if u asked us if their was any mass or friton

Explanation:

7 0
2 years ago
What is energy? Where does it come from? What does it do? Explain in 5 or more sentences please! :)
Vlada [557]

Answer:

Energy is defined as the ability to do work. Forms of energy could be kinetic energy or potential energy. Thermal or heat energy can originate from a hot object such as the sun. Energy is used to produce work. Electrical energy for lighting purposes and heating in homes and factories.

Explanation:

Energy is defined as the ability to do work and can be in various forms such as kinetic energy, potential energy, thermal, chemical, electrical energy etc.

Energy origination depends on the type of energy form in discussion. Thermal or heat energy can originate from a hot object such as the sun or an iron box, chemical energy originates from the interaction of atoms and molecules and electrical energy can be initiated by movements of electrons.

Energy is used to produce work. Different forms of energy can do different tasks such as;

Heat energy for heating water

Electrical energy for lighting purposes

Geothermal energy for producing heat and electricity

Nuclear energy for production of nuclear power

Chemical energy for facilitating chemical reactions

4 0
2 years ago
A spring-loaded gun can fire a projectile to a height h if it is fired straight up. if the same gun is pointed at an angle of 45
Naily [24]
When firing straight up:
v^2 = u^2 - 2gh, where v = final velocity = 0, u = initial velocity, g = gravitational acceleration, h = maximum height attained.

Then,
0 = u^2 - 2gh
u = Sqrt (2gh) ---- (1)

When firing at 45°,
Initial velocity, U = u Sin 45 = Sqrt (2gh)·Sin 45

Maximum height, H = U^2*(Sin Ф)^2/2g

substituting;
H = [Sqrt (2gh)·Sin 45]^2*(Sin 45)^2]/2g
H = [2gh*(Sin 45)^2*(Sin 45)^2]/2g
H = [h*(Sin 45)^4] = h/4

Therefore, maximum height when the gun fires at 45° is a quarter of maximum height when the gun fires vertically up.
6 0
3 years ago
Plssssss look at the picture i need it right hurry pls
Karo-lina-s [1.5K]

Answer:

it is B

Explanation:

5 0
2 years ago
Read 2 more answers
An archer needs to hit a bullseye on a target at eye level of 60ft away. If the archer fires the arrow from the eye level with a
ohaa [14]
The time of fly of a projectile to the same level as it was launched is 2(v_y)/g=2(47sin(25))/g. We multiply this by the v_x to get the distance. Thus, the distance is <span>2(47sin(25))/g*47cos(25)=86.2. This is a overshoot!</span>
7 0
3 years ago
Other questions:
  • Sound waves are actually a form of what kind of energy?
    11·2 answers
  • How many centimeters are there in a length 676 inches?
    14·1 answer
  • A high diver of mass 60.0 kg steps off a board 10.0 m above the water and falls vertical to the water, starting from rest. If he
    9·1 answer
  • You have a horizontal cathode ray tube (CRT) for which the controls have been adjusted such that the electron beam should make a
    8·1 answer
  • An empty office chair is at rest on a floor. Consider the following forces:. 1. A downward force due to gravity;. 2. An upward forc
    7·1 answer
  • Wo siblings are arguing over what way to pull a 10 kg wagon. Boris wants to pull it to the right. Boris puts 220 N of force on t
    11·1 answer
  • A 4.00-m long rod is hinged at one end. The rod is initially held in the horizontal position, and then released as the free end
    15·1 answer
  • Question 15 of 15
    9·1 answer
  • Which refers to the rate of change in velocity?
    13·1 answer
  • Which forces are contact forces give one example of each​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!