The lower layer is thought to be hard and rough
Well, we don't know if it's the CLOSEST one, but it's closer than the other ones on this print-out.
There are actually three clues to this in the seismograms:
1). The waves from the tremor reach the Wink station first ... the P wave gets there 50 seconds before Chicago and 3 whole minutes before Tampa.
2). They are stronger (greater amplitude) at Wink than at Chicago or Tampa.
3). The delay between the P wave and the S wave is the smallest at Wink. This delay between the two waves grows as the detector is farther from the quake.
Answer:
3.28 m/s
Explanation:
From the question,
Applying newtons ,
F = mv²/r........................ Equation 1
Where m = mass of the rock, v = speed, r = radius of the circle, F = Centriputal force.
But,
Centriputal force is equal to the weight of the rock
F = mg................. Equation 2
Equate equation 2 into equation 1
mg = mv²/r
Therefore,
v = √gr...................... Equaion 3
Given: r = 2.2/2 = 1.1 m
Constant: g = 9.8 m/s²
Substitute into equation 3
v = √(9.8×1.1)
v = √(10.78)
v = 3.28 m/s
Hence the minimum speed is 3.28 m/s
Answer: below
Explanation: 1kg of steel is slightly heavier than 1 kg of feathers. 1 kg of feather will displace more air as the density of feather is very less comparitively. More the volume displaced more is the upthrust and less the apparent weight.
Hi!
The answer would be 22.5m
<h3>Explanation</h3>
To calculate the distance the ball travels, you would need to apply the following formula from the equations of motion for an accelerating object:
2as = v^2 - u^2
Where a is acceleration due to gravity, 9.8m/s^2
s is the distance traveled by the object (height of ball in this case)
v is the final velocity, which we know will be zero at the point where the ball reaches maximum height.
u is the initial velocity, which is known to us as 21m/s
Rearranging the equation to solve for the height:
s = (v^2 - u^2 ) / 2a
s = ( 0^2 - 21^2 ) / 2(-9.8)
s = - 441/ - 19.6
s = 22.5m
<em>Note: since gravity is acting against the object's motion, it will be negative </em>
<em>Hope this helps!</em>
