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Basile [38]
3 years ago
9

Of 100 students, 32 are taking Calculus, 29 are taking French, and 13 are taking both Calculus and French, if a student is picke

d at random
what is the probability that the student is taking Calculus or French?
(Reduce fraction to lowest form)​
Mathematics
1 answer:
Elodia [21]3 years ago
4 0
<h2>Answer:</h2><h2>The probability that the student is taking Calculus or French =  \frac{12}{25}</h2>

Step-by-step explanation:

The total number of students = 100

Let A represents calculus and B represents French

The no of students taking calculus = 32

The no of students taking French = 29

The no of students taking calculus and french = 13

the probability that the student is taking Calculus or French = ?

P (AUB) = P(A) + P(B) - P(A∩B)

= \frac{32}{100} + \frac{29}{100} - \frac{13}{100}

= \frac{48}{100}

Reducing to lowest fraction,  it becomes \frac{12}{25}

The probability that the student is taking Calculus or French =  \frac{12}{25}

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