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Basile [38]
3 years ago
9

Of 100 students, 32 are taking Calculus, 29 are taking French, and 13 are taking both Calculus and French, if a student is picke

d at random
what is the probability that the student is taking Calculus or French?
(Reduce fraction to lowest form)​
Mathematics
1 answer:
Elodia [21]3 years ago
4 0
<h2>Answer:</h2><h2>The probability that the student is taking Calculus or French =  \frac{12}{25}</h2>

Step-by-step explanation:

The total number of students = 100

Let A represents calculus and B represents French

The no of students taking calculus = 32

The no of students taking French = 29

The no of students taking calculus and french = 13

the probability that the student is taking Calculus or French = ?

P (AUB) = P(A) + P(B) - P(A∩B)

= \frac{32}{100} + \frac{29}{100} - \frac{13}{100}

= \frac{48}{100}

Reducing to lowest fraction,  it becomes \frac{12}{25}

The probability that the student is taking Calculus or French =  \frac{12}{25}

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Remember

log_a(b)=c translates to a^c=b
and
log_a(b^c)=clog_a(b)
so


4096=16^3
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log_{3x-2}(16^3)=3
3log_{3x-2}(16)=3
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log_{3x-2}(16)=1
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4 years ago
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Sergeu [11.5K]

Answer:

5 pints per hour.

Step-by-step explanation:

Morning:

Given:

Number of strawberries packed in every 4 minutes = 3

∴ Number of strawberries packed in every one minute = \frac{3}{4}

So, number of strawberries packed in every 60 minutes = \frac{3}{4}\times 60=45

1 hour = 60 minutes.

So, strawberries are packed at a rate of 45 pints per hour in the morning.

Afternoon:

Number of strawberries packed in every 3 minutes = 2

∴ Number of strawberries packed in every one minute = \frac{2}{3}

So, number of strawberries packed in every 60 minutes = \frac{2}{3}\times 60=40

1 hour = 60 minutes.

So, strawberries are packed at a rate of 40 pints per hour in the afternoon.

Difference between the packing rates is given as:

Morning rate - Afternoon rate = 45 - 40 = 5 pints per hour.

So, she packed 5 more pints in one hour in the morning than in the afternoon.

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