Question

Of 100 students, 32 are taking Calculus, 29 are taking French, and 13 are taking both Calculus and French, if a student is picked at random
what is the probability that the student is taking Calculus or French?
(Reduce fraction to lowest form)​

Answer 1

Answer:

The probability that the student is taking Calculus or French =  $\frac{12}{25}$

Step-by-step explanation:

The total number of students = 100

Let A represents calculus and B represents French

The no of students taking calculus = 32

The no of students taking French = 29

The no of students taking calculus and french = 13

the probability that the student is taking Calculus or French = ?

P (AUB) = P(A) + P(B) - P(A∩B)

= $\frac{32}{100}$ + $\frac{29}{100}$ - $\frac{13}{100}$

= $\frac{48}{100}$

Reducing to lowest fraction,  it becomes $\frac{12}{25}$

The probability that the student is taking Calculus or French =  $\frac{12}{25}$