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neonofarm [45]
3 years ago
11

Extreme temperature changes or increased moisture speed up the weathering rate.

Chemistry
1 answer:
____ [38]3 years ago
6 0

that is a true statement

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Identify three pairs of statements that could be used to start developing a taxonomic key for a mouse, turtle, flamingo, and cat
Zanzabum

Answer:

A dichotomous key is a tool that allows the user to determine the identity of items and organisms in the natural world. ... In each step, the user is presented with two statements based on characteristics of the organism. If the user makes the correct choice every time, the name of the organism will be revealed at the end

Explanation:

4 0
3 years ago
What is the pH of a solution made by mixing equal volumes of 1 M sodium acetate and 1 M acetic acid? (The pK of acetic acid is 4
Solnce55 [7]

Answer:

The pH is 4.76 (option C)

Explanation:

pH of a solution = TO BE DETERMNED

[sodium acetate] = 1M   ;   [acetic acid] = 1M

K = [H+] [A-] / [HA] 

K = [H+] [1] / [1] 

K = H  

pH = pK

⇒ now pH is equal to pK

⇒ The value of pK is given which is 4.76

⇒ This means the value of the pH is also 4.76

3 0
3 years ago
Heat transferred by direct contact from one particle of matter to another is know as ____.
Alex777 [14]

Answer:

B

Explanation:

6 0
3 years ago
Read 2 more answers
What does paranthasis mean on an ion
Morgarella [4.7K]
It means that they are bonded together
5 0
3 years ago
A 250. ML sample of 0.3M HCl is partially neutralized by the addition of 100. ML of 0.25M NaOH.Find the concentration of hydroch
Dahasolnce [82]

Answer:- 0.143 M

Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:

HCl(aq)+NaOH(aq)\rightleftharpoons NaCl(aq)+H_2O(l)

Let's calculate the initial moles of HCl and the moles of NaOH added to it:

250.mL(\frac{1L}{1000mL})(\frac{0.3molHCl}{1L})

= 0.075 mol HCl

100.mL(\frac{1L}{1000mL})(\frac{0.25molNaOH}{1L})

= 0.025 mol NaOH

Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.

Remaining moles of HCl = 0.075 - 0.025 = 0.050

Total volume of the resulting solution = 0.250 L + 0.100 L = 0.350 L

So, the concentration of HCl in the resulting solution = \frac{0.050mol}{0.350L}

= 0.143 M

Hence, the concentration of HCl acid in the resulting solution is 0.143 M.


6 0
4 years ago
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