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3 years ago

How many liters of a 4.0 M CaCl2 solution would contain 2 moles of CaCl2?

Chemistry

1 answer:

nekit [7.7K]3 years ago

5 0

Answer:

The answer to your question is 0.5 liters

Explanation:

Data

[CaCl₂] = 4.0 M

number of moles = 2

volume = ?

Process

To solve this problem use the formula of Molarity and solve it for volume, substitute the values and simplify.

-Formula

Molarity = moles / volume

-Solve for volume

Volume = moles / molarity

-Substitution

Volume = 2/4

-Simplification

Volume = 0.5 liters.

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3 years ago

What is the concentration of OH − and pOH in a 0.00066 M solution of Ba ( OH ) 2 at 25 ∘ C? Assume complete dissociation.

Allushta [10]

<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is $1.32\times 10^{-3}M$ and 2.88 respectively

<u>Explanation:</u>

We are given:

Concentration of barium hydroxide = 0.00066 M

The chemical equation for the dissociation of barium hydroxide follows:

$Ba(OH)_2\rightarrow Ba^{2+}+2OH^-$

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$pOH=-\log[OH^-]$

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$[OH^-]=(2\times 0.00066)=1.32\times 10^{-3}M$

Putting values in above equation, we get:

$pOH=-\log(1.32\times 10^{-3})\\\\pOH=2.88$

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3 years ago

Cuantos moles de CO2 se requieren para reaccionar con 2 moles de Ba (OH)2

EastWind [94]

Answer:

hola soy jess, tu respuesta esta aqui

¿cuantos moles de CO2 se requiere para reaccionar 2 moles de Ba(OH)2

2 mol Ba(OH)₂ × \frac{1molCO_{2} }{1molBa (OH)_{2}}

1molBa(OH)

1molCO

= 2 moles CO₂

Explanation:

espero que pueda ayudarte

hermana/hermano

lo que

hahahaha

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Deffense [45]

Answer:

Explanation:

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