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NISA [10]
3 years ago
9

If the rate of appearance of O2 in the reaction: 2O3(g)-----3O2(g) is 0.250 M/s over the first 5.50 s, how much oxygen will form

during this time?
Chemistry
1 answer:
maks197457 [2]3 years ago
8 0

<u>Given:</u>

Rate of appearance of O2 = 0.250 M/s

Time period = 5.50 s

<u>To determine:</u>

The concentration of O2 formed

<u>Explanation:</u>

2O3 (g) ↔ 3O2 (g)

Rate of appearance of O2 = 1/3 * Δ[O2]/Δt

Based on the given data:

0.250 M/s = 1/3 * [O2]/5.50 s

[O2 ] = 0.250 Ms⁻¹ * 3 * 5.50 s = 4.125 M

Ans: Amount of oxygen formed is 4.13 M


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yulyashka [42]

Answer:

162g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Next, we shall determine the number of mole of water, H2O produced by the reaction of 3 moles of C2H6.

This can be obtained as follow:

From the balanced equation above,

2 moles of C2H6 reacted to produce 6 moles of H2O.

Therefore, 3 moles of C2H6 will react to produce = (3 x 6)/2 = 9 moles of H2O.

Therefore, 9 moles of H2O is produced from the reaction.

Finally, we shall convert 9 moles of H2O to grams.

This can be done as shown below:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mole of H2O = 9 moles

Mass of H2O =..?

Mole = mass / molar mass

9 = mass of H2O /18

Cross multiply

Mass of H2O = 9 x 18

Mass of H2O = 162g

Therefore, 162g of H2O were produced from 3 moles of C2H6.

8 0
3 years ago
Solid cesium bromide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell
Oxana [17]

Answer:

\mathbf {density \ d  =4.4845 \ g/cm^3}

Explanation:

Let recall the crystal structure of CsBr obtains a BCC structure. In a BCC structure, there exist only two atom per cell.

The density d of CsBr in g/cm³ can be calculated by using the formula:

\mathtt{ density \ d  = \dfrac{z \times molar\  mass  \ (M)}{ edge \ length \ (a)  \ \times avogadro's \ number \ (N)}}

where;

z = 1 mole of CsBr

edge length = 428.7 pm = (4.287 × 10⁻⁸)³ cm

molar mass of CsBr = 212.81 g/mol

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\mathtt{ density \ d  = \dfrac{1 \times 212.81}{(4.287 \times 10^{-8})^3 \times 6.023 \times 10^{23}}}

\mathtt{ density \ d  = \dfrac{ 212.81}{47.4540533}}

\mathbf {density \ d  =4.4845 \ g/cm^3}

5 0
3 years ago
If you had a mixture of ethanol, glycerol, ethylene glycol, methanol, and water, how could you separate these five substances ou
leonid [27]

Fractional distillation

Explanation:

The best way to separate the mixtures out is through the process of fractional distillation.

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We see that the liquids in the mixture have different boiling points. In this process, the mixture is heated in a distillation column. When the boiling point of any component is reached, it will rise up in the column and can be channeled to a condenser where it is cooled and collected.

The liquid with the least boiling point is first separated with the one with the highest boiling is recovered last:

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                Glycerol                290⁰C

Learn more:

Physical properties brainly.com/question/10972073

#learnwithBrainly

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