Answer:
-1m
Explanation:
I'm assuming it means that you treat the distance travelled as a displacement vector (distance of a particular direction and magnitude)
If he turns 180 degrees, he is travelling in the exact opposite direction to his original direction of travel. Therefore if he was travelling 5m in one direction, then afer his turn he travels 6m in the exact opposite direction. Opposite directions can be interpreted as the negative of the original direction.
Resultant vectors are the sum of vectors.
The sum of vectors is equal to 5m + - 6m = -1m
Answer:
![v = 1.71 m/s](https://tex.z-dn.net/?f=v%20%3D%201.71%20m%2Fs)
Explanation:
As we know that there is no friction in the bowl so total mechanical energy is conserved here
So we can say that
initial potential energy of the butter = final kinetic energy at the bottom
so we can say
![mgH = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=mgH%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
here we can solve it for speed v
![v^2 = 2gH](https://tex.z-dn.net/?f=v%5E2%20%3D%202gH)
now plug in all values in it
![v^2 = (2 \times 9.8\times 0.150)](https://tex.z-dn.net/?f=v%5E2%20%3D%20%282%20%5Ctimes%209.8%5Ctimes%200.150%29)
![v = 1.71 m/s](https://tex.z-dn.net/?f=v%20%3D%201.71%20m%2Fs)
Answer:
A) Amplitude
Explanation:
The angular frequency ω = √k/m
maximum acceleration = ω²A ; A is amplitude
frequency of oscillation = ω / 2π
maximum force = m x ω²A
so maximum acceleration ,frequency of oscillation and maximum force
all depend on ω so they will change due to change of mass . Hence amplitude will remain constant.
Answer:
from
charge.
Explanation:
Given
The magnitude of the first charge is ![Q_1=3.5\ nC](https://tex.z-dn.net/?f=Q_1%3D3.5%5C%20nC)
The magnitude of the second charge is ![Q_2=5\ nC](https://tex.z-dn.net/?f=Q_2%3D5%5C%20nC)
charge must be placed in between the two charges to establish equilibrium
The electrostatic force is given by
![F=\dfrac{kq_1q_2}{r^2}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bkq_1q_2%7D%7Br%5E2%7D)
Equilibrium will be established when force by both the charges balance out each other. Suppose
is placed at a distance of
cm from
. So, we can write
![\Rightarrow \dfrac{k(3.5)(-6)}{x^2}=\dfrac{k(5)(-6)}{(40-x)^2}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7Bk%283.5%29%28-6%29%7D%7Bx%5E2%7D%3D%5Cdfrac%7Bk%285%29%28-6%29%7D%7B%2840-x%29%5E2%7D)
Canceling similar terms
![\Rightarrow \left [ \dfrac{40-x}{x}\right ]^2=\dfrac{10}{7}\\\\\Rightarrow \dfrac{40-x}{x}=\sqrt{\dfrac{10}{7}}=1.195\\\\\Rightarrow 40-x=1.195x\\\Rightarrow 40=2.195x\\\Rightarrow x=18.22\ cm](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cleft%20%5B%20%20%5Cdfrac%7B40-x%7D%7Bx%7D%5Cright%20%5D%5E2%3D%5Cdfrac%7B10%7D%7B7%7D%5C%5C%5C%5C%5CRightarrow%20%5Cdfrac%7B40-x%7D%7Bx%7D%3D%5Csqrt%7B%5Cdfrac%7B10%7D%7B7%7D%7D%3D1.195%5C%5C%5C%5C%5CRightarrow%2040-x%3D1.195x%5C%5C%5CRightarrow%2040%3D2.195x%5C%5C%5CRightarrow%20x%3D18.22%5C%20cm)
Thus, the equilibrium position is
from
charge.
Answer:
False
Explanation:
Acceleration is the rate of change of velocity
Acceleration
the negative acceleration means the speed of the object decreases
Negative acceleration does not mean that velocity will also negative
For example if the the speed of the object decreases from 20 m/sec to 15 m/sec in 5 sec then acceleration will be
here acceleration is negative but velocity is positive