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Drupady [299]
3 years ago
12

Volume of an block is 5 cm3. If the density of the block is 250 g/cm3, what is the mass of the block ?​

Physics
1 answer:
wlad13 [49]3 years ago
7 0

Answer:

The mass of the block is 1250g.

Explanation:

Given that the formula for density is ρ = mass/volume. Then you have to substitute the values into the formula :

ρ =  \frac{mass}{volume}

Let density = 250,

Let volume = 5,

250 =  \frac{m}{5}

m = 250 \times 5

m = 1250g

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A rocket weighs 9800N (opposing force) what is it mass? What netforce moves the rocket? What applied force gives it a vertical a
Slav-nsk [51]

For the first part of this question, consider that "weight" can be described as mass x acceleration of gravity. Weight is expressed in Newtons. To solve for mass in this case, simply divide 9800N by 9.8m/s^2 (Earth's gravitational acceleration). This will give you a mass of 1000 kg. This mass is moved due to the net force supplied by the normal force from the rocket "pushing" off of Earth.

For the second part, we will use the equation F = ma, which is Newton's second law. For this, we know the m, or mass, is 1000 kg. Also, we know the a, or acceleration, will be 4 m/s^2. To solve for force, we will multiply both of these values. This gives a force of 4000 N. I hope this clears things up!

6 0
3 years ago
Unpolarized light with an intensity of (25.0 A) units is passed through two successive polarizing filters, the first with its po
coldgirl [10]

Answer:

the intensity of the light after passing through the two polarizing filters is 4.11 units  

 

Explanation:

Given the data in the question;

the intensity of an unpolarized light; I₀ = 25.0 units

when the unpolarized light passes through the first polarizer, its intensity reduces to half of its initial value;

⇒ I₁ = I₀/2 = 25/2 = 12.5 units

the angle between the transmission axes of two polarizers is;

∅ = 55° - 0° = 55°

The intensity of the light after passing through two polarizing filters will be;

I₂ = I₁cos²∅      

we substitute

I₂ = 12.5 × cos²(55)

I₂ = 12.5 × 0.3289899

I₂ = 4.11 units

Therefore, the intensity of the light after passing through the two polarizing filters is 4.11 units

6 0
3 years ago
4 of
Maksim231197 [3]

Answer:

all of the above????

Explanation:

my teacher told me.

8 0
3 years ago
In a vacuum, two particles have charges of q1 and q2, where q1 = +3.11 μC. They are separated by a distance of 0.241 m, and part
lesya [120]

Answer:

Charge of particle 2, q_2=-7.13\ \mu C

Explanation:

Given that,

Charge 1, q_1=3.11\ \mu C=3.11\times 10^{-6}\ C

The distance between charges, r = 0.241 m

Force experienced by particle 1, F = 3.44 N

We need to find the magnitude of electric charge 2. It can be calculated using formula of electrostatic force. It is given by :

F=k\dfrac{q_1q_2}{r^2}

q_2=\dfrac{Fr^2}{kq_1}

q_2=\dfrac{3.44\times (0.241)^2}{9\times 10^9\times 3.11\times 10^{-6}}

q_2=7.13\times 10^{-6}\ C

or

q_2=7.13\ \mu C

So, the magnitude of electric charge 2 is q_2=7.13\ \mu C. Since, the force is attractive then the magnitude of charge 2 must be negative.

5 0
3 years ago
Người ta ném một hòn bi theo phương ngang với vận tốc ban đầu là 15m/s và nó rơi xướng đất sau 4s. Bỏqua sức cản của không khí v
Juliette [100K]

Answer:

h = 80m L = 60m

Explanation:

Độ cao Ng ta ném hòn bi là

t=\sqrt{\frac{2h}{9}} => 4^2 = \frac{2h}{10}

h= 80m

Tầm bay xa:

L= Vo . t = 15.4 = 60m

Chúc học tốt nghen

5 0
3 years ago
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