I think it is -3.99 x 102 j
Answer:B
Explanation:
Given
Distance of astronaut From asteroid x is ![r_x=140 km](https://tex.z-dn.net/?f=r_x%3D140%20km)
Distance of astronaut From asteroid Y is ![r_y=581 km](https://tex.z-dn.net/?f=r_y%3D581%20km)
Suppose M,M_x,M_y be the masses of Astronaut , asteroid X and Y
If the astronaut is in equilibrium then net gravitational force on it is zero
![F_x=F_y](https://tex.z-dn.net/?f=F_x%3DF_y)
![\frac{GMM_x}{r_x^2}=\frac{GMM_y}{r_y^2}](https://tex.z-dn.net/?f=%5Cfrac%7BGMM_x%7D%7Br_x%5E2%7D%3D%5Cfrac%7BGMM_y%7D%7Br_y%5E2%7D)
cancel out the common terms we get
![\frac{M_x}{r_x^2}=\frac{M_y}{r_y^2}](https://tex.z-dn.net/?f=%5Cfrac%7BM_x%7D%7Br_x%5E2%7D%3D%5Cfrac%7BM_y%7D%7Br_y%5E2%7D)
![\frac{M_x}{M_y}=(\frac{r_x}{r_y})^2](https://tex.z-dn.net/?f=%5Cfrac%7BM_x%7D%7BM_y%7D%3D%28%5Cfrac%7Br_x%7D%7Br_y%7D%29%5E2)
![\frac{M_x}{M_y}=(\frac{140}{581})^2](https://tex.z-dn.net/?f=%5Cfrac%7BM_x%7D%7BM_y%7D%3D%28%5Cfrac%7B140%7D%7B581%7D%29%5E2)
![\frac{M_x}{M_y}=0.05806\approx 0.0581](https://tex.z-dn.net/?f=%5Cfrac%7BM_x%7D%7BM_y%7D%3D0.05806%5Capprox%200.0581)
V=r/t
Speed equals displacement over the time
V=100/9.92=10.08ms^-1
Answer: C. -1.16 meters/second2
Explanation:
A= v/t (velocity/time)
in this case: v=7 and t=6
So, A= 7/6
A=1.16
The graph is decreasing so accelleration would be negative
A= <u>-1.16 meters/second2</u>
<u>Option C!</u> ; )
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Explanation:
electrical potential = (6.6-3.4)/0.20
= 16 uc/m