Answer:
Hindi ko po alam pero subukan ko pong sagutan yan
Answer:
The reaction is not in equilibrium and moves to the left until Q equals Kc.
Explanation:
Hello!
First we must check that the equation is balanced.
We propose the constant Kc for the balanced equation.
We propose Q for the balanced equation.
We calculate the value of Q and compare with Kc
If Q = Kc the reaction is in equilibrium.
If Q> Kc the reaction moves from right to left.
If Q <Kc the reaction shifts from left to right.
We obtain the value of Kc from the value of Kp. If the variation of mol is zero Kp = Kc
Successes with your homework!
Once you balance the enquation you "switch partners" of the element (negative charge to positive charge)
Answer:
Percent yield = 7.1%
Explanation:
The general reaction of the problem is:
Ca(OH)₂ + CO₂ → H₂O + CaCO₃
To solve this question we need to find theoretical yield using the amount of carbon dioxide added because:
Percent yield = Actual yield (3.22g) / Theoretical yield * 100
Theoretical yield is the maximum amount of product that could be obtained. To find it we need to convert the mass of CO₂ to moles. The moles of CO₂ = Moles of CaCO₃:
<em>Moles CO₂ -Molar mass: 44.01g/mol):</em>
20.0g * (1mol / 44.01g) = 0.454 moles CO₂ = Moles of CaCO₃ produced
<em>Mass CaCO₃ = Theoretical yield -Molar mass: 100.09g/mol-:</em>
0.454 moles * (100.09g / mol) = 45.5g of CaCO₃ = Theoretical yield.
Replacing:
Percent yield = 3.22g / 45.5g * 100
<h3>Percent yield = 7.1%</h3>
Answer:
B
Explanation:
Trust me I've had problems like these