Answer:
What are you doing stepbro?
Explanation:
In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.
The average pea weighs between 0.1 and 0.36 grams.
If we take the lower value (0.1 g/pea), the number of peas in 454 g is:

If we take the higher value (0.36 g/pea), the number of peas in 454 g is:

In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.
You can learn more about conversion factors here: brainly.com/question/1844638
Nuclear decay or radioactive decay is a process by which the nucleus of an unstable atom loses energy that is in terms of its mass. The radioactivity may cause an atom to lose whichever of its subatomic particles.
The explanation as why some of the atoms go through nuclear decay while others do not its because of the stability of some atoms. Atoms usually tend to follow octet rule, those which do not follow through this may experience the nuclear decay.
Answer:
Air can be described as: Mass and Mixture of Gases
Mass is defined as how much stuff an object contains - and by stuff, I mean matter, like atoms and molecules. And even though you can't see it, air has a lot of atoms and molecules. Air is a gas (as opposed to a liquid or a solid) and contains about 78% nitrogen, 21% oxygen, and 1% argon.
Explanation:
Answer:
Here's what I get
Step-by-step Explanation
(a) Effect of dilution
There will be no effect on the volume of NaOH needed.
The amount of HCl will be halved, so the amount of NaOH will be halved.
However, the concentration of NaOH is also halved, so you will need twice the volume.
You will be back to the same volume as before dilution.
(b) Net ionic equation
Molecular: HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)
Ionic: H⁺(aq) + Cl⁻(aq) + Na⁺(aq) + OH⁻(aq) ⟶ Na⁺(aq) + Cl⁻(aq) + H₂O(l)
Net ionic: H⁺(aq) + OH⁻(aq) ⟶ H₂O(l)
(c) Proton acceptor
H⁺ is the proton. OH⁻ accepts the proton and forms water.
(d) Moles of HCl

(e) Equivalence point
The equivalence point is the point at which the titration curve intersects the pH 7 line.
(f) Schematic representation
Assume the box for 0.10 mol·L⁻¹ HCl contains four black dots (H⁺) and four open circles (Cl⁻).
The 0.20 mol·L⁻¹ solution is twice as concentrated.
It will contain eight black dots and eight open circles.