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yKpoI14uk [10]
3 years ago
7

. Calculate the pH of a solution made by dissolving 1.87 g of sodium caproate, NaC6H11O2, Kb =

Chemistry
1 answer:
scoray [572]3 years ago
8 0

Answer:

Hindi ko po alam pero subukan ko pong sagutan yan

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Convert 16.8 L of nitrogen monoxide gas at STP to grams .
german

Answer:

See explanation

Explanation:

1 mole of a gas occupies 22.4 L

x moles occupies 16.8 L

x = 1 mole *  16.8 L/22.4 L

x = 0.75 moles

number of moles = mass/molar mass

mass =  number of moles  * molar mass

mass =  0.75 moles * 30.01 g/mol = 22.5075 g = 2.25 * 10^1 g

the coefficient of the scientific notation answer = 2.25

the exponent of the scientific notation answer = 1

significant figures are there in the answer = 6

the right most significant figure in the answer = 3

2.

number of moles = 12.5g/38g/mol = 0.3289 moles

1 mole occupies 22.4 L

0.3289 moles occupies 0.3289 moles * 22.4 L/1 mole

= 7.36736 L = 7.36736 * 10^0 L= 7.37 * 10^0 L

the coefficient of the scientific notation answer =7.37

the exponent of the scientific notation answer = 0

significant figures are there in the answer = 6

the right most significant figure in the answer= 3

8 0
3 years ago
Gift points I'm sad..........​
Naddika [18.5K]

Awh, why are you sad? :(

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3 years ago
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Which of the following is not a form of energy?
Dafna1 [17]
The answer is pressure
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3 years ago
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When this element was discovered, it exhibited luster and malleability, and it reacted very vigorously with water. This element
rjkz [21]
The answer is potassium
5 0
3 years ago
Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest
balu736 [363]

Answer:

Cost to supply enough vanillin is 3.2\$

Explanation:

Threshold limit of vanillin in air is 2.0\times 10^{-11}g per litre means there should be 2.0\times 10^{-11}g of vanillin in 1L of air to detect aroma of vanillin.

1ft^{3}=28.32L

So, 5.0\times 10^{7}ft^{3}=(5.0\times 10^{7}\times 28.32)L

So amount of vanillin should be present to detect = (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g

As cost of 50 g vanillin is 112\$ therefore cost of  (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)gvanillin = (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32\times 112)\$ = 3.2\$

5 0
3 years ago
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