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Elanso [62]
3 years ago
5

Look at the diagram of a fuel cell below.

Chemistry
2 answers:
VladimirAG [237]3 years ago
5 0

Answer:

It is a electrolyte.

Explanation:

I took the test.

Ymorist [56]3 years ago
4 0
I’m pretty sure it’s abode and cathode
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In atomic science, the z number refers to the number of __________ in the nucleus of an atom.
Sliva [168]
By convention, the symbol Z is assigned to the number of protons in the nucleus, or simply, the atomic number of an element. This is actually used when you want to determine the effective nuclear charge of a specific electron of an element. The equation is:

Z* = Z - S
where
Z* is the effective nuclear charge
Z is the atomic number
S is the number of electrons between the electron in question and the nucleus

There is due to a phenomenon called the shielding effect. This effect states that the farther the electron is from the nucleus, the lesser is its pull of force to the nucleus. That is the reason why the valence electrons (outermost electrons) are the ones always involved in chemicals reactions. Because they are not that strongly bonded to the nucleus of an atom.
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True or false? Steel is a chemical element.
Irina-Kira [14]
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At one point in the Bike Trip described in the passage, you traveled 1 kilometer in 0.1 hours. What was your speed during that t
stealth61 [152]

Answer:

v = 10 km/h

Explanation:

Step 1: Given data

  • Distance traveled in the Bike Trip (d): 1 km
  • Time elapsed in the Bike Trip (t): 0.1 h

Step 2: Calculate the speed in the Bike Trip

The speed (v) is equal to the distance traveled divided by the time elapsed. We will use the following mathematical expression.

v = d/t

v = 1 km/0.1 h

v = 10 km/h

The speed is 10 kilometers per hour.

7 0
3 years ago
A 13.30 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 13.00 grams of CO2 and 2
a_sh-v [17]

<u>Answer:</u> The empirical and molecular formula for the given organic compound is CHO_2 and C_2H_2O_4

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=13.00g

Mass of H_2O=2.662g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 13.00 g of carbon dioxide, \frac{12}{44}\times 13.00=3.54g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 2.662 g of water, \frac{2}{18}\times 2.662=0.296g of hydrogen will be contained.

Mass of oxygen in the compound = (13.30) - (3.54 + 0.296) = 9.464 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.54g}{12g/mole}=0.295moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.296g}{1g/mole}=0.296moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{9.465g}{16g/mole}=0.603moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.295 moles.

For Carbon = \frac{0.295}{0.295}=1

For Hydrogen = \frac{0.296}{0.295}=1

For Oxygen = \frac{0.603}{0.295}=2.044\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 1 : 2

Hence, the empirical formula for the given compound is CHO_2

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 90.04 g/mol

Mass of empirical formula = 45 g/mol

Putting values in above equation, we get:

n=\frac{90.04g/mol}{45g/mol}=2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 2)}H_{(1\times 2)}O_{(2\times 2)}=C_2H_2O_4

Hence, the empirical and molecular formula for the given organic compound is CHO_2 and C_2H_2O_4

3 0
3 years ago
What information does the third quantum number of an electron give? A. The direction the electron in spinning B. The energy leve
Juli2301 [7.4K]

The information that the third quantum number of an electron gives is the direction the electron in spinning. That is option A.

<h3>What are quantum numbers?</h3>

Quantum number are those numbers that are used to specify the properties of the atomic orbitals and the electrons in those orbitals.

The types of quantum numbers include the following:

  • principal,

  • azimuthal,

  • magnetic, and spin.

The third quantum number is shows the direction of the electron while spinning through specifying its angular momentum.

Learn more about orbitals here:

brainly.com/question/14361631

#SPJ1

4 0
2 years ago
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