<u><em>Diffusion:
</em></u><em> in diffusion particles move from area of higher concentration to the area of lower concentration..
</em><u><em>causes:
</em></u><em>the movement of particles allow them ti disperse,,, when molecules are close to each other they collide with each other and push each other apart so they spread in the whole area... :)</em><u><em>
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Answer:
The woman's distance from the right end is 1.6m = (8-6.4)m.
The principles of moments about a point or axis running through a point and summation of forces have been used to calculate the required variable.
Principle of moments: the sun of clockwise moments must be equal to the sun of anticlockwise moments.
Also the sun of upward forces must be equal to the sun of downward forces.
Theses are the conditions for static equilibrium.
Explanation:
The step by step solution can be found in the attachment below.
Thank you for reading this solution and I hope it is helpful to you.
Answer:
Both A and C
Explanation:
I just got it correct on Edg
Answer:
a)1815Joules b) 185Joules
Explanation:
Hooke's law states that the extension of a material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically;
F = ke where;
F is the applied force
k is the elastic constant
e is the extension of the material
From the formula, k = F/e
F1/e1 = F2/e2
If a force of 60N causes an extension of 0.5m of the string from its equilibrium position, the elastic constant of the spring will be ;
k = 60/0.5
k = 120N/m
a) To get the work done in stretching the spring 5.5m from its position,
Work done by the spring = 1/2ke²
Given k = 120N/m, e = 5.5m
Work done = 1/2×120×5.5²
Work done = 60× 5.5²
Work done = 1815Joules
b) work done in compressing the spring 1.5m from its equilibrium position will be gotten using the same formula;
Work done = 1/2ke²
Work done =1/2× 120×1.5²
Works done = 60×1.5²
Work done = 135Joules
Solution :
a). Using Gauss's law :
, 
.........(1)
Let 
in equation (1)
Therefore, 
.............(2)
....................(3)
Therefore, 
.............(4)
Now differentiating the equation (4) w.r.t. 'b', we get
Thus the radius for the inner cylinder conductor is
b). For the energy storage, substitute the radius in (4), we get
This is the amount of energy stored in the conductor.
