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schepotkina [342]
3 years ago
13

Assume that a vaulter is able to carry a vaulting pole while running as fast as Carl Lewis in his world record 100-m dash (aroun

d 12 m/s). Also assume that all of the vaulter’s kinetic energy is transformed into gravitational potential energy. What vaulting height could that person attain?
Physics
1 answer:
xeze [42]3 years ago
7 0

Answer:

hello

Explanation:

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Astronauts on a distant planet set up a simple pendulum of length 1.2 m. The pendulum executes simple harmonic motion and makes
Iteru [2.4K]

Answer:

If you use P = 2 * pi * (L / g)^1/2  for the period of the simple pendulum

g = 4 * pi^2 * 1.2 / 2.8^2 = 6.04 m/s2

Note: omega = 2 pi * f = 2 pi / P  and omega = (g / L)^1/2

7 0
3 years ago
A 12,000 kg railroad car is traveling at 2 m/s when it strikes another 10,000 kg railroad car that is at rest. If the cars lock
Degger [83]

Answer:

The final speed of the railroad car

V= 1.14 \frac{m}{s}

Explanation:

v_{1}=2.1\frac{m}{s} \\m_{1}=12000kg\\v_{2}=0\frac{m}{s} \\m_{2}=10000kg \\v_{t}=?

m_{1}*v_{1}+m_{2}*v_{2}= (m_{1}+m_{2})*v_{t}\\v_{t}=\frac{m_{1}*v_{1}}{(m_{1}+m_{2})} \\v_{t}=\frac{12000kg*2.1\frac{m}{s} }{(12000+10000)kg} \\v_{t}=1.14 \frac{m}{s}

That's the final speed of the both railroad car

4 0
3 years ago
Help me , what is the properties of fluids ? ​
rodikova [14]
Some of the most fundamental concepts of fluid properties are temperature, density, and composition.
4 0
3 years ago
Read 2 more answers
You throw a ball with a speed of 25.0 m/s at an angle of 40.0â—¦ above the horizontal directly toward a wall. The wall is 22.0 m
Alina [70]

The ball takes about 1.15 seconds to reach the wall

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem!

This problem is about Projectile Motion

<u>Given:</u>

initial speed = u = 25 m/s

angle of speed = θ = 40.0°

horizontal distance = x = 22.0 m

<u>Unknown:</u>

time taken by the ball = t = ?

<u>Solution:</u>

<em>We will use this following formula to find the time taken by the ball to reach the wall:</em>

x = u_x t

x = u \cos \theta ~t

22 = 25 \cos 40^o ~t

t = 22 \div ( 25 \cos 40^o )

t \approx 1.15 \texttt { seconds}

\texttt{ }

<h2>Conclusion :</h2>

The ball takes about 1.15 seconds to reach the wall

\texttt{ }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Projectile , Motion , Horizontal , Vertical , Release , Point , Ball , Wall

7 0
3 years ago
Read 2 more answers
El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es
topjm [15]

Answer:

P₁ = 219.3 Pa

Explanation:

This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.

Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.

              P₁ = P₂

pressure is defined by

             P = F / A

we subtitute

             F₁ / A₁ = F₂ / A₂

             F₁ = F₂ A₁ / A₂

the area in a circle is

             A = π r² = π d² / 4

we substitute

            F₁ = F₂ (d₁ / d₂)²

we calculate

           F₁ = 17640 (2/32)²

           F₁ = 68.9 N

Having the force to be applied we can find the air pressure on the small plunger

          P₁ = F₁ / A₁

          P₁ = F₁ 4 / π d₁²

let's calculate

          P₁ = 68.9 4 / (π 0.02²)

          P₁ = 219.3 Pa

3 0
3 years ago
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