Assume that a vaulter is able to carry a vaulting pole while running as fast as Carl Lewis in his world record 100-m dash (aroun
1 answer:
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Explanation:
The first equation of motion in kinematics is given by :
.....(1)
u is initial speed
a is acceleration
v is final speed
t is time
Equation (1) is valid when the object is moving with constant acceleration. This equation gives relation between velocity and time.
Speed of Dayshawn travelling towards his home is 12 m/s
Speed of her mom towards his school is 5 m/s
They both starts at same time so whenever they will meet on their path the sum of the distance covered by Dayshawn and distance covered by his mom must be equal to the total distance of school and home
Now let say they both meet after "t" time when they starts motion
so we can write the total distance between school and home as
here d = 6492 m
= speed of dayshawn
= speed of his mom
now by solving the above equation
so they will meet after 381.9 s from start which will be 3.36 minutes from there start
Also at this time the distance covered by her mom will be
so they will meet at distance 1909.4 m from their home
Answer:
3.5 cm
Explanation:
mass, m = 50 kg
diameter = 1 mm
radius, r = half of diameter = 0.5 mm = 0.5 x 10^-3 m
L = 11.2 m
Y = 2 x 10^11 Pa
Area of crossection of wire = π r² = 3.14 x 0.5 x 10^-3 x 0.5 x 10^-3
= 7.85 x 10^-7 m^2
Let the wire is stretch by ΔL.
The formula for Young's modulus is given by
ΔL = 0.035 m = 3.5 cm
Thus, the length of the wire stretch by 3.5 cm.