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AlexFokin [52]
3 years ago
10

Honeybees can see light in the ________ range of the electromagnetic spectrum. question 8 options:

Physics
2 answers:
ELEN [110]3 years ago
8 0
<span>ultraviolet

Have a great day!</span>
vampirchik [111]3 years ago
8 0

Your question is missing the options. I've found the complete question online. It is as follows:

Honeybees can see light in the ________ range of the electromagnetic spectrum.

A. beta

B. infrared

C. ultraviolet

D. gamma

Answer:

The correct option is C. ultraviolet.

Explanation:

Even though visible to honeybees, the ultraviolet light is not visible to human eyes because its frequency is higher, and its wavelength is shorter than our brains are capable to perceive. Ultraviolet wavelength ranges from 10nm to 400 nm, which is longer than X-rays, but shorter than visible light for us.

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Number these from least (1) to most (5) inertia.
worty [1.4K]

Answer:

 1. A feather

2. A baseball

3. a small car

4. A truck

5. A large train

Explanation:

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3 years ago
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You have been hired as a technical consultant for an early-morning cartoon series for children to make sure that the science is
katen-ka-za [31]

The initial potential energy of the wagon containing gold boxes will enable

it roll down the hill when cut loose.

The Lone Ranger and Tonto have approximately <u>5.1 seconds</u>.

Reasons:

Mass wagon and gold = 166 kg

Location of the wagon = 77 meters up the hill

Slope of the hill = 8°

Location of the rangers = 41 meters from the canyon

Mass of Lone Ranger, m₁ = 65 kg

Mass of Tonto m₂ = 66 kg

Solution;

Height of the wagon above the level ground, h = 77 m × sin(8°) ≈ 10.72 m

Potential energy = m·g·h

Where;

g = Acceleration due to gravity ≈ 9.81 m/s²

Potential energy of wagon, P.E. ≈ 166 × 9.81 × 10.72 = 17457.0912

Potential energy of wagon, P.E. ≈ 17457.0912 J

By energy conservation, P.E. = K.E.

K.E. = \mathbf{\dfrac{1}{2} \cdot m \cdot v^2}

Where;

v = The velocity of the wagon a the bottom of the cliff

Therefore;

\dfrac{1}{2} \times 166 \times v^2 = 17457.0912

v = \sqrt{\dfrac{17457.0912}{\dfrac{1}{2} \times 166} } \approx 14.5

Velocity of the wagon, v ≈ 14.5 m/s

Momentum = Mass, m × Velocity, v

Initial momentum of wagon = m·v

Final momentum of wagon and ranger = (m + m₁ + m₂)·v'

By conservation of momentum, we have;

m·v = (m + m₁ + m₂)·v'

\therefore v' = \mathbf{ \dfrac{m \cdot v}{(m + m_1 + m_2)  }}

Which gives;

\therefore v' = \dfrac{166 \times 14.5}{(166 + 65 + 66)  } \approx 8.1

The velocity of the wagon after the Ranger and Tonto drop in, v' ≈ 8.1 m/s

Time = \dfrac{Distance}{Velocity}

\mathrm{The \ time \ the\ Lone \  Ranger \  and  \ Tonto \  have,  \ t} = \dfrac{41 \, m}{8.1 \, m/s} \approx 5.1 \, s

The Lone Range and Tonto have approximately <u>5.1 seconds</u> to grab the

gold and jump out of the wagon before the wagon heads over the cliff.

Learn more here:

brainly.com/question/11888124

brainly.com/question/16492221

5 0
2 years ago
The British attempted to break the land-speed record and the sound barrier using a jet-powered car. They made their attempt in t
jolli1 [7]

Your answer is B.

The relationship between medium temperature and speed of sound is a direct relationship: when one factor increases, the other increases as is shown in graph B. The British would choose the the time of day which would give the lowest speed of sound, because this would be easiest to break. Graph B shows that the lowest speed of sound would occur with the lowest air temperature - in the morning.

4 0
3 years ago
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A car was moving at 14 m/s After 30 s, its speed increased to 20 m/s. What was the acceleration during this time ( need help fas
Arada [10]

Answer:let initial velocity u=14m/s

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a=0.2m/s^2

Explanation:

Acceleration is the change in velocity with respect to time.

7 0
3 years ago
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Klio2033 [76]
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B: In the case of the light bulb the 95J of energy transferred as heat is wasted energy as it is not useful because the purpose of the device is to produce light.

SORRY I ONLY HAVE ANSWERS FOR A AND B
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2 years ago
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