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Mandarinka [93]
2 years ago
10

Why does an empty soda bottle float on water and a full soda bottle sank in water?

Physics
2 answers:
telo118 [61]2 years ago
6 0

Answer:

becuase if there is no soda in bottle it gives gravity but if there is a soda in bottle it will sank becuase it is heavy and the water can no longer to give it a gravity. maybe I'm wrong

AlladinOne [14]2 years ago
3 0

Answer:

hope will help you understand it :)

Explanation:

The difference in the amount of dissolved sweeteners leads to a difference in density. Cans of regular soda tend to be more dense than water, so they sink. Cans of diet soda are usually less dense than water, so they float.

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Science Virtual Lab: Smithsonian Museum Of Natural History
Viefleur [7K]

Your answers are correct. You have to read the plaques in the virtual lab to find the answers. So it shows you read them.

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5 0
3 years ago
If the half-life of tritium (hydrogen-3) is 12.3 years, how much of
tatyana61 [14]

Answer:

0.0000076 grams

Explanation:

We're given the half life of Tritium to be 12.3 years. In order to find out the amount of substabce remaining:

Let's first find how many 'half lives' are in 250 years.

n =  \frac{250}{12.3}  = 20.325

Now what is half life? It means the time taken for a given quantity of an element to lose half it's mass.

So in 12.3 years we can find that The amount of 250 g of Tritium will be 250/2 = 125 g. In 24.6 years we'll have 125/2 = 62.5 g

So now we can devise a formula:

m =  \frac{original \: amount}{ {2}^{n} }

Where m is the remaining amount and n is th number of half lives in the time given.

Using this formula we can calculate:

m =  \frac{10}{ {2}^{20.325} }

Doing this calculation we get:

m = 0.0000076 \: g

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4 0
2 years ago
A large solar panel on a spacecraft in Earth orbit produces 1.0 kW of power when the panel is turned toward the sun. What power
Mandarinka [93]

Answer:

e*P_s = 11 W

Explanation:

Given:

- e*P = 1.0 KW

- r_s = 9.5*r_e

- e is the efficiency of the panels

Find:

What power would the solar cell produce if the spacecraft were in orbit around Saturn

Solution:

- We use the relation between the intensity I and distance of light:

                                  I_1 / I_2 = ( r_2 / r_1 ) ^2

- The intensity of sun light at Saturn's orbit can be expressed as:

                                  I_s = I_e * ( r_e / r_s ) ^2

                                  I_s = ( 1.0 KW / e*a) * ( 1 / 9.5 )^2

                                  I_s = 11 W / e*a

- We know that P = I*a, hence we have:

                                  P_s = I_s*a

                                  P_s = 11 W / e

Hence,                       e*P_s = 11 W

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Answer:

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3 0
3 years ago
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