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S_A_V [24]
10 months ago
6

What is the temperature change of an 36-gram sample of water that had absorbed 695 Joules of heat? C = 4.18 J/g K

Chemistry
1 answer:
maks197457 [2]10 months ago
6 0

The temperature change of a 36-gram sample of water is <u>4.61 K</u>

Temperature is the degree of the average kinetic energy of the debris in an item. while the temperature will increase, the movement of this debris additionally will increase. Temperature is measured with a thermometer or a calorimeter.

heat = msΔt

     695 Joule = 36 ×  4.186 × Δt

Δt   =  695/ 36 ×  4.186

      = <u>4.61 K</u>

Temperature is just a dimension that indicates the common kinetic energy of 1 atom or molecule. as a result, when we are saying something is warm or bloodless, we're generally using any other reference point to define the hotness and coldness of a frame.

Learn more about temperature here:-brainly.com/question/2339046

#SPJ9

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Describe the reactions during the electrolysis of water in an electrolytic cell. Group of answer choices Oxygen and hydrogen are
Ann [662]

Answer:

Oxygen is oxidized and hydrogen is reduced.

Explanation:

Let's consider the redox reaction during the electrolysis of water in an electrolytic cell.

2 H₂O ⇒ 2 H₂ + O₂

The corresponding half-reactions are:

2 e⁻ + 2 H₂O ⇒ H₂ + 2 OH⁻

2 H₂O ⇒ O₂ + 4 H⁺ + 4 e⁻

Oxygen is oxidized since its oxidation number increases from -2 to 0.

Hydrogen is reduced since its oxidation number decreases from +1 to 0.

6 0
3 years ago
3. ¿Cuál de las siguientes operaciones es correcta para calcular el número de moles de hidrógeno necesarios para producir 6 mole
Aloiza [94]

Answer:

the answer is d that is 6×2/3

4 0
3 years ago
Hospital patients are administered oxygen from an pressurized
VashaNatasha [74]

Answer:

32000atm

Explanation:

Using Boyle's law equation;

P1V1 = P2V2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (

V2 = final volume (L)

According to the question below:

P1 = 160.0 atm

P2 = 3.0 atm

V1 = 600L

V2 = ?

Using P1V1 = P2V2

160 × 600 = 3 × V2

96000 = 3V2

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V2 = 32000atm

5 0
2 years ago
The density of water at 40°c is 0.992 g/ml. what is the volume of 3.45 g of water at this temperature?
wariber [46]
3.45÷0.992=3.48ml
...
8 0
3 years ago
How many grams of NH3 can be dissolved in 50 grams of water at 50oC?
weqwewe [10]

15 grams of  NH3 can be dissolved

<h3>Further explanation</h3>

Given

50 grams of water at 50°C

Required

mass of NH3

Solution

Solubility is the maximum amount of a substance that can dissolve in some solvents. Factors that affect solubility  

  • 1. Temperature:
  • 2. Surface area:
  • 3. Solvent type:
  • 4. Stirring process:

We can use solubility chart (attached) to determine the solubility of NH3 at 50°C

From the graph, we can see that the solubility of NH3 in 100 g of water at 50 C is 30 g

So that the solubility in 50 grams of water is:

= 50/100 x 30

= 15 grams

5 0
3 years ago
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