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S_A_V [24]
1 year ago
6

What is the temperature change of an 36-gram sample of water that had absorbed 695 Joules of heat? C = 4.18 J/g K

Chemistry
1 answer:
maks197457 [2]1 year ago
6 0

The temperature change of a 36-gram sample of water is <u>4.61 K</u>

Temperature is the degree of the average kinetic energy of the debris in an item. while the temperature will increase, the movement of this debris additionally will increase. Temperature is measured with a thermometer or a calorimeter.

heat = msΔt

     695 Joule = 36 ×  4.186 × Δt

Δt   =  695/ 36 ×  4.186

      = <u>4.61 K</u>

Temperature is just a dimension that indicates the common kinetic energy of 1 atom or molecule. as a result, when we are saying something is warm or bloodless, we're generally using any other reference point to define the hotness and coldness of a frame.

Learn more about temperature here:-brainly.com/question/2339046

#SPJ9

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Which of the following is true for a chemical reaction at equilibrium?
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Read 2 more answers
The half life for the radioactive decay of carbon- to nitrogen- is years. Suppose nuclear chemical analysis shows that there is
ivann1987 [24]

Answer:

Age of rock = 6.12 × 10³ years

Note: The question is incomplete.A similar but complete question is given below.

The half-life for the radioactive decay of carbon-14 to nitrogen-14 is 5.73 x 10^3 years. Suppose nuclear chemical analysis shows that there is 0.523mmol of nitrogen-14 for every 1.000 mmol of carbon-14 in a certain sample of rock.

Calculate the age of the rock. Round your answer to 2 significant digits.

Explanation:

The half-life of a radioactive material is the time taken for half the atoms in the atomic nucleus of a material to disintegrate.

The half-life for the radioactive decay of carbon-14 to nitrogen-14 is given as 5.73 x 10³ years. This means that given 1 mole of carbon-14 is present initially, after one half-life, 0.5 moles of carbon-14 would remain.

Number of millimoles of carbon-14 remaining = 1 - 0.523 = 0.477 mmol

Number of half-lives that the carbon-14 has undergone is determined as follows:

Amount remaining = (1/2)ⁿ

where nnis number of half-lives

0.5 mmol = one half-life

0.5 = (1/2)¹

O.477 = (1/2)ⁿ = (0.5)ⁿ

㏒₀.₅(0.477) = n

n = ㏒(0.477)/㏒(0.5)

n = 1.067938829

Age of the rock = number of half-lives × half-life

Age of rock = 1.067938829 × 5.73 × 10³ years

Age of rock = 6.12 × 10³ years

6 0
3 years ago
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