40 g of CaCO3 is how many moles of CaCO3? 10 moles 0.4 moles 40 moles 100 moles
1 answer:
You might be interested in
Given :
A compound has a molar mass of 129 g/mol .
Empirical formula of compound is C₂H₅N .
To Find :
The molecular formula of the compound.
Solution :
Empirical mass of compound :
Now, n-factor is :
Multiplying each atom in the formula by 3 , we get :
Molecular Formula, C₆H₁₅N₃