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3 years ago

What happens in reactions that take place under ideal conditions

Chemistry

1 answer:

Gnoma [55]3 years ago

6 0

When a reaction takes place under ideal conditions all of the reactants are completely converted into products

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I really need help please someone help me?!.<br><br> Those are all the questions.

natima [27]

Answer:

question two is most likely you can describe the shape as a twisted ladder, thats what I learned in school.

Explanation:

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3 years ago

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Which of the following releases matter? A.engaging a car exhaust system B.picking up iron filings with a magnet C.turbines spinn

igomit [66]

A- engaging a car exhaust system

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4 years ago

5 atoms Pb to mol Pb

jek_recluse [69]

Answer:

0,83 x 10-²³ mol

Explanation:

n=N/Na

n=5:(6,02 x 10²³)

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3 years ago

What’s the answer to this ( the proton has a ____ charge and it is found in the ____

Ksenya-84 [330]

ANSWER:

A proton has a "positive charge" and is found in the nucleus.

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3 years ago

Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . Calculate t

Sedbober [7]

Answer:

Approximately $6.30\times 10^{-3}\;\rm mol$ .

Explanation:

The gallium here is likely to be produced from a $\rm NaGaO_2\, (aq)$ solution using electrolysis. However, the problem did not provide a chemical equation for that process. How many electrons will it take to produce one mole of gallium?

Note the Roman Numeral " $\mathtt{(III)}$ " next to $\rm Ga$ . This numeral indicates that the oxidation state of the gallium in this solution is equal to $+3$ . In other words, each gallium atom is three electrons short from being neutral. It would take three electrons to reduce one of these atoms to its neutral, metallic state in the form of $\rm Ga\, (s)$ .

As a result, it would take three moles of electrons to deposit one mole of gallium atoms from this gallium $\mathtt{(III)}$ solution.

How many electrons are supplied? Start by finding the charge on all the electrons in the unit coulomb. Make sure all values are in their standard units.

$t = \rm 80.0\; min = 80.0\; min \times 60\;s \cdot min^{-1} = 4800\; s$ .

$Q = I \cdot t = \rm 0.380 \; A \times 4800 \; s = 1.824\times 10^3\; C$ .

Calculate the number of electrons in moles using the Faraday's constant. This constant gives the size of the charge (in coulombs) on each mole of electrons.

$\begin{aligned} n(\text{electrons}) &= \frac{Q}{F} \cr &= \rm \dfrac{1.824\times 10^3\; C}{96485.332\; C \cdot mol^{-1}}\cr &\approx \rm 1.89\times 10^{-2}\; mol \end{aligned}$ .

It takes three moles of electrons to deposit one mole of gallium atoms $\rm Ga\, (s)$ . As a result, $\rm 1.89\times 10^{-2}\; mol$ of electrons would deposit $\displaystyle \rm \frac{1}{3}\times 1.89\times 10^{-2}\; mol \approx 6.30\times 10^{-3}\; mol$ of gallium atoms $\rm Ga\, (s)$ .

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3 years ago