Question

1

Answer 1

Answer:

The molarity of the solution is 0,99M

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g-----1 mol NaCl

145 g ---------x= (145 g x 1 mol NaCl)/58, 5 g= 2,48 mol NaCl

2,5 L solution------ 2, 48 mol NaCl

1 L solution------x= (1 L solutionx 2, 48 mol NaCl)/2,5L solution

x=0,99 mol NaCl---> The solution is 0,99 molar (0,99 M)

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