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Ber [7]
3 years ago
6

To navigate, a porpoise emits a sound wave that has a wavelength of 4.9 cm. The speed at which the wave travels in seawater is 1

522 m/s. Find the period of the wave.
Physics
1 answer:
bekas [8.4K]3 years ago
5 0

Frequency can be defined as the ratio between the speed of the wave and its wavelength, that is

f= \frac{v}{\lambda}

At the same time, the frequency is the inverse of the Period so

T = \frac{1}{f}

If we join the two expressions we will have to

T = \frac{\lambda}{v}

Replacing we have that

T = \frac{4.9*10^{-2}}{1522}

T = 3.219*10^{-5} s

Therefore the period of the wave is 3.219*10^{-5} s

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Answer:

A. v_{3}=12.17m/s

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A. Since the two vehicles become entangled the final mass is:

m_{3}=102kg+103kg=205kg

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p_{1}=p_{2}

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v_{3}=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{3} }=\frac{(102kg)(5.79m/s)+(103kg)(18.5m/s)}{(205kg)}

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C. The change in kinetic energy is:

ΔK=K_{2}-K_{1} =\frac{1}{2}m_{3}v_{3}^{2}-(\frac{1}{2}m_{1}v_{1}^{2}+\frac{1}{2}m_{2}v_{2}^{2})

ΔK=\frac{1}{2}(205)(12.17)^{2}-(\frac{1}{2}(102)(5.79)^{2}+\frac{1}{2}(103)(18.5)^{2})=-4.13x10^{3}J

ΔK=-4.13x10^{3}J

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For safety reasons, a worker’s eye travel time in a certain operation must be separated from the manual elements that follow. Th
iogann1982 [59]

Answer:

The answer is 12.67 TMU

Explanation:

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