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Alina [70]
3 years ago
14

Highest density if electrostatic charge in a metal is found in​

Physics
1 answer:
arsen [322]3 years ago
8 0
There’s no picture so how r we supposed to answer it
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What layer is above the troposphere
goldenfox [79]
The stratosphere is the layer above the troposphere 
6 0
3 years ago
Read 2 more answers
What unit is used to measure the period of a wave?
mixer [17]

Answer:

D. Meters/Seconds

Explanation:

The time period of a wave is measured in seconds.

A typical wave involves both time and distance.  Consider a sound wave, which is basically a periodic modulation of the local air pressure.  We "hear" the sound because our ears respond to the variations of pressure.

The most common metric of a sound wave is frequency.  This is the rate at which the change in pressure occurs, and is measured in cycles per second, formally known as "hertz".  The period is the inverse of frequency andl has the units of seconds per cycle, commonly stated simply as seconds.

4 0
2 years ago
A lacrosse ball that is thrown straight upwards reaches a maximum height of 4.5 m. At what initial velocity was it thrown? (note
shtirl [24]

Answer:

The initial velocity was 9.39 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

The ball is thrown straight upward with initial velocity u

The ball reaches a maximum height of 4.5 m

At the maximum height velocity v = 0

The acceleration of gravity is -9.8 m/s²

We need to find the initial velocity

The best rule to find the initial velocity is <em>v² = u² + 2ah</em>, where v is

the final velocity, u is the initial velocity, a is the acceleration of

gravity and h is the height

⇒ v = 0 , h = 4.5 m , a = -9.8 m/s²

⇒ 0 = u² + 2(-9.8)(4.5)

⇒ 0 = u² - 88.2

Add 88.2 to both sides

⇒ 88.2 = u²

Take square root for both sides

⇒ u = 9.39 m/s

<em>The initial velocity was 9.39 m/s</em>

5 0
3 years ago
A ball is dropped from a tower that is 206 m high, How long does it take to reach the ground?
Slav-nsk [51]

It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.

From the question given above, the following data were obtained:

Height (H) = 206 m

<h3>Time (t) =? </h3>

NOTE: Acceleration due to gravity (g) = 10 m/s²

The time taken for the ball to get to the ground can be obtained as follow:

H = ½gt²

206 = ½ × 10 × t²

206 = 5 × t²

Divide both side by 5

t^{2}  = \frac{206}{5}\\\\ t^{2} = 41.2

Take the square root of both side

t = \sqrt{41.2}

<h3>t = 6.42 s</h3>

Therefore, it will take 6.42 s for the ball to get to the ground.

Learn more: brainly.com/question/24903556

7 0
3 years ago
What is the mass if an object moving with a speed of 9m/s and a kinetic energy if 2000 J​
stepladder [879]

Solve for mass:

m= 2k/v(squared)

m=2000(2)/9(squared))

m=49.383 kilograms

7 0
3 years ago
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