You can make a laser go through someone’s skin in some circumstances you can’t do that with other light sources
Answer: The classical complement pathway for complement activation is initiated by antigen-antibody complexes with the antibody isotypes IgG and IgM.
Explanation: The classical complement pathway typically requires antigen-antibody complexes (immune complexes) for activation (specific immune response), whereas the alternative pathway can be activated by C3 hydrolysis, foreign material, pathogens, or damaged cells.
After activation, a series of proteins are recruited to generate C3 convertase, which cleaves the C3 protein. The C3b component of the cleaved C3 binds to C3 convertase to generate C5 convertase, which cleaves the C5 protein. The cleaved products attract phagocytes to the site of infection and tags target cells for elimination by phagocytosis. In addition, the C5 convertase initiates the terminal phase of the complement system, leading to make appear the membrane attack complex. The membrane attack complex creates a pore on the target cell's membrane, inducing cell lysis and death.
Answer:
The light bulb would glow brighter.
Explanation:
Resistance is the opposition to current flow and in Ohm's law is represented as a constant in the equation V = IR with V the voltage, I the current and R the resistance.
Now let's assume we are in a series circuit that has only one path for electricity to follow to better explain what would happen to a light bulb if the voltage increased but the resistance stayed the same. Based on ohm's law equation, the voltage is directly proportional to the current and the resistance is constant. An increase in the voltage is therefore an increase in the current which flows throught the light bulb making it glow brighter while a decrease in voltage results in a decrease in current flowing through the light bulb making it dim.
Answer:
c) ![4.2*10^{-5}C](https://tex.z-dn.net/?f=4.2%2A10%5E%7B-5%7DC)
Explanation:
Coulomb's law says that the force exerted between two charges is inversely proportional to the square of distance between them, and is given by the expression:
![F=\frac{kq_{1}q_{2}}{r^{2}}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bkq_%7B1%7Dq_%7B2%7D%7D%7Br%5E%7B2%7D%7D)
where k is a proportionality constant with the value ![k=9*10^{9}\frac{Nm^{2}}{C^{2}}](https://tex.z-dn.net/?f=k%3D9%2A10%5E%7B9%7D%5Cfrac%7BNm%5E%7B2%7D%7D%7BC%5E%7B2%7D%7D)
In this case
, so we have:
![F=\frac{kq^{2}}{r^{2}}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bkq%5E%7B2%7D%7D%7Br%5E%7B2%7D%7D)
Solving the equation for q, we have:
![kq^{2}=Fr^{2}](https://tex.z-dn.net/?f=kq%5E%7B2%7D%3DFr%5E%7B2%7D)
![q^{2}=\frac{Fr^{2}}{k}](https://tex.z-dn.net/?f=q%5E%7B2%7D%3D%5Cfrac%7BFr%5E%7B2%7D%7D%7Bk%7D)
![q=\sqrt{\frac{Fr^{2}}{k}}](https://tex.z-dn.net/?f=q%3D%5Csqrt%7B%5Cfrac%7BFr%5E%7B2%7D%7D%7Bk%7D%7D)
Replacing the given values:
![q=\sqrt{\frac{4.0N*(2.0m)^{2}}{9*10^{-9}\frac{Nm^{2}}{C^{2}}}}](https://tex.z-dn.net/?f=q%3D%5Csqrt%7B%5Cfrac%7B4.0N%2A%282.0m%29%5E%7B2%7D%7D%7B9%2A10%5E%7B-9%7D%5Cfrac%7BNm%5E%7B2%7D%7D%7BC%5E%7B2%7D%7D%7D%7D)
![q=4.2*10^{-5}C](https://tex.z-dn.net/?f=q%3D4.2%2A10%5E%7B-5%7DC)