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3 years ago

Which is true for a substance that releases energy?

1 answer:

5 0

The correct answer is option A, that is, the energy release decreases the molecular motion and the kinetic energy of the substance.

When a substance discharges energy, it signifies that the energy of the molecules is now being transferred into the substance with whom it comes in contact with or into the atmosphere. Thus, at the time of the discharge of energy, the motion of molecules diminishes and as a consequence, the kinetic energy of the molecules will reduce.

Therefore, it can be concluded that for a substance the energy discharged diminishes the molecular motion and the kinetic energy of the substance.

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What dose microwave radiation have in common with visible light

forsale [732]

"We gain strength, and courage, and confidence by each experience in which we really stop to look fear in the face...we must do that which we think we cannot." - Eleanor Roosevelt

8 0

3 years ago

A 1.00 L sample of a gas at a pressure of 1.000atm is compressed to 0.25 L at a constanttemperature. What is the new pressure of

lord [1]

Answer:

<h3>The answer is 4 atm </h3>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new pressure

$P_2 = \frac{P_1V_1}{V_2} \\$

From the question we have

$P_2 = \frac{1 \times 1}{0.25} = \frac{1}{0.25} \\$

We have the final answer as

Hope this helps you

5 0

3 years ago

What is the bond order for the carbon-nitrogen bond in acetonitrile, CH3CN? 2.2.0 03.0.5 C. 3.0 d. 1.5 0.1.0

marin [14]

Answer:

C. 3.0

Explanation:

Bond order is number of the bonding pairs of the electrons between two atoms.

For $CH_3CN$ ,

The total number of the valence electrons = 2(4) + 1(5) + 3(1) = 16

The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,

The Lewis structure is:

H : C : C : : : N :

Bond pairs between C and N is 3

7 0

3 years ago

Read 2 more answers

calculate the speed of an electron if its de broglie wavelength is twice its displacement in one second

valkas [14]

Answer:

The speed of an electron is 0.01908 m/s.

Explanation:

De-Broglie wavelength is given by:

$\lambda=\frac{h}{mv}$

where, $\lambda$ = wavelength of a particle

h = Planck's constant = $6.626\times 10^{-34}Js$

m = mass of particle

v = velocity of the particle

Velocity of an electron = v

Mass of an electron = $9.1\times 10^{-31}kg$

Wavelength of electron is twice the displacement in seconds which is velocity of an electron.

Then.wavelength of an electron = $\lambda =2v$

$\lambda =2v=\frac{6.626\times 10^{-34}Js}{9.1\times 10^{-31}kg\times v}$

v = 0.01908 m/s

The speed of an electron is 0.01908 m/s.

5 0

3 years ago

A 13.5 g sample of an unknown gas occupies 5.10 L at 149.83 kPa and 301 K. What is the molar mass of the gas ?

alisha [4.7K]

Answer:

The molar mass of the gas is 44.19 g/mol

Explanation:

Amount of sample of gas = m = 13.5 g

Volume occupied by the gas = V = 5.10 L

Pressure of the gas = P = 149.83 KPa

1 KPa = 0.00986 atm

P = $149.83 \textrm{ KPa} \times 0.00986 \textrm{ atm/KPa} = 1.48 \textrm{ atm}$

Assuming M g/mol to be the molar mass of the gas

Assuming the gas is behaving as an ideal gas

$\textrm{PV} =\textrm{nRT} \\\textrm{PV} = \displaystyle \frac{m}{M}\textrm{ RT } \\1.48 \textrm{ atm}\times 5.10 \textrm{ L} = \displaystyle \frac{13.5 \textrm{ g}}{M}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 301\textrm{K} \\M = 44.19 \textrm{ g/mol}$

The molar mass of gas is 44.19 g/mol

7 0

4 years ago