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3 years ago

**answer asap with explanation please

Chemistry

1 answer:

pantera1 [17]3 years ago

3 0

Answer:

It is a double replacement reaction, and all four compounds are different.

Step-by-step explanation:

The equation for the reaction is

$\underbrace{\hbox{ ionic compound + ionic compound}}_{\hbox{reactants}} \longrightarrow \underbrace{\hbox{ ionic compound + ionic compound}}_{\hbox{products}}$

This must be a double replacement reaction, in which the metal cations trade partners and all four compounds are different.

(A) and (C) are <em>wrong</em>, because single replacements involve elements in reactions of the type

element + compound ⟶ element + compound

(D) is <em>wrong</em> because, if each compound retained the same set of ions, there would be no reaction.

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Determine the missing species:

Galina-37 [17]

Answer: 4. $^{0}_{-1}\textrm{e}$ and $^{0}_{1}\textrm{e}$

Explanation:

a) The given reaction is $^{41}_{20}\textrm{Ca}+^{x}_{y}\textrm{X}\rightarrow ^{41}_{19}\textrm {K}$

As the mass on both reactant and product side must be equal:

$41+x=41$

$x=0$

As the atomic number on both reactant and product side must be equal:

$20+y=19$

$y=-1$

$^{41}_{20}\textrm{Ca}+^{0}_{-1}\textrm{e}\rightarrow ^{41}_{19}\textrm {K}$

b) $^{15}_{8}\textrm{O}\rightarrow ^{15}_{7}\textrm{N}+^{x}_{y}\textrm{X}$

Total mass on reactant side = total mass on product side

15 =15 + x

x = 0

Total atomic number on reactant side = total atomic number on product side

8 = 7 + y

y = 1

$^{15}_{8}\textrm{O}\rightarrow ^{15}_{7}\textrm{N}+^{0}_{1}\textrm{e}$

5 0

2 years ago

Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as

zubka84 [21]

Answer:

Explanation:

MnO₂(s) + 4 HCl(aq) = MnCl₂(aq) + 2 H₂O(l) + Cl₂

87 g 22.4 x 10³ mL

volume of given chlorine gas at NTP or at 760 Torr and 273 K

= 175 x ( 273 + 25 ) x 715 / (273 x 760 )

= 179.71 mL

22.4 x 10³ mL of chlorine requires 87 g of MnO₂

179.4 mL of chlorine will require 87 x 179.4 / 22.4 x 10³ g

= 696.77 x 10⁻³ g

= 696.77 mg .

6 0

3 years ago

Sort these species into isoelectronic groups. It doesn\'t matter which group goes in which box, so long as the correct species a

OleMash [197]

Answer : The isoelectronic groups are:

$He,Be^{2+},Li^{+}$

$N^{3-},Mg^{2+}$

$S^{2-},Ti^{4+},K^{+}$

Explanation :

Isoelectronic : It is defined as the compound or molecule having the same number of electrons and the same number of electronic structure.

The element is helium. The number of electrons are 2.
The element is beryllium. The number of electrons are 4. The number of electrons in $Be^{2+}$ = 4 - 2 = 2
The element is lithium. The number of electrons are 3. The number of electrons in $Li^{+}$ = 3 - 1 = 2
The element is nitrogen. The number of electrons are 7. The number of electrons in $N^{3-}$ = 7 + 3 = 10
The element is neon. The number of electrons are 10.
The element is sulfur. The number of electrons are 16. The number of electrons in $S^{2-}$ = 16 + 2 = 18
The element is magnesium. The number of electrons are 12. The number of electrons in $Mg^{2+}$ = 12 - 2 = 10
The element is titanium. The number of electrons are 22. The number of electrons in $Ti^{4+}$ = 22 - 4 = 18
The element is potassium. The number of electrons are 19. The number of electrons in $K^{+}$ = 19 - 1 = 18

The isoelectronic groups are:

$He,Be^{2+},Li^{+}$

$N^{3-},Mg^{2+}$

$S^{2-},Ti^{4+},K^{+}$

7 0

2 years ago

Under which class of substitution reaction does this reaction appear to fall

liberstina [14]

This reaction is most likely to fall under SN2 because the thing called carbonication does not occur in SN1. The carbon forms a partial bond with the nucleophile during the intermediate phase and the leaving group. So for this question the reaction will fall under SN2.

3 0

3 years ago

In the chemical formula H2O , which description explains what the 2 represents?

alukav5142 [94]

the number of hydrogen atoms

8 0

3 years ago

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