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3 years ago

**answer asap with explanation please

Chemistry

1 answer:

pantera1 [17]3 years ago

3 0

Answer:

It is a double replacement reaction, and all four compounds are different.

Step-by-step explanation:

The equation for the reaction is

$\underbrace{\hbox{ ionic compound + ionic compound}}_{\hbox{reactants}} \longrightarrow \underbrace{\hbox{ ionic compound + ionic compound}}_{\hbox{products}}$

This must be a double replacement reaction, in which the metal cations trade partners and all four compounds are different.

(A) and (C) are <em>wrong</em>, because single replacements involve elements in reactions of the type

element + compound ⟶ element + compound

(D) is <em>wrong</em> because, if each compound retained the same set of ions, there would be no reaction.

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Is it true barium ion Games to electrons to make its valence shell full

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Answer:

It is false

Explanation:

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This is because, barium is electropositive and not electronegative.

As with most metals, barium will prefer to lose two electrons when forming bonds.
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3 years ago

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3 years ago

Read 2 more answers

Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. 4.90 g of su

GaryK [48]

Answer:

Mass H2SO4 = 3.42 grams

Mass of lead acetate = 0 grams

Mass PbSO4 = 4.58 grams

Mass of CH3COOH = 1.81 grams

Explanation:

Step 1: Data given

Mass of sulfuric acid = 4.90 grams

Molar mass of sulfuric acid = 98.08 g/mol

Mass of lead acetate = 4.90 grams

Molar mass of lead acetate = 325.29 g/mol

Step 2: The balanced equation

H2SO4 + Pb(C2H3O2)2 → PbSO4 + 2CH3COOH

Step 3: Calculate moles

Moles = mass / molar mass

Moles H2SO4 = 4.90 grams / 98.08 g/mol

Moles H2SO4 = 0.0500 moles

Moles lead acetate = 4.9 grams / 325.29 g/mol

Moles lead acetate = 0.0151 moles

Step 4: Calculate the limiting reactant

For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH

The limiting reactant is lead acetate. It will completzly be consumed (0.0151 moles). H2SO4 is in excess. There will react 0.0151 moles. There will remain 0.0500 - 0.0151 = 0.0349 moles

Step 5: Calculate moles of products

For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH

For 0.0151 moles lead acetate we'll have 0.0151 moles PbSO4 and 2*0.0151 = 0.0302 moles CH3COOH

Step 6: Calculate mass

Mass = moles * molar mass

Mass H2SO4 = 0.0349 moles * 98.08 g/mol

Mass H2SO4 = 3.42 grams

Mass PbSO4 = 0.0151 moles * 303.26 g/mol

Mass PbSO4 = 4.58 grams

Mass of CH3COOH = 0.0302 moles * 60.05 g/mol

Mass of CH3COOH = 1.81 grams

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3 years ago

Determine the gram-formula mass of stearin acid C17H35COOH

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Answer:

284.48 g/mol

Explanation:

You can find the molar mass of any molecule by looking at a periodic table and adding up all of the masses of each element. When you do this with stearic acid, you get somewhere around 284.5 g/mol. Hope this helped!

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3 years ago