Answer:
The work done depends upon the <u> Force</u> applied and <u>Displacement</u> produced.
Explanation:
Definition: Work is said to be on a body only if a force acting on it causes a displacement in its direction
.
In other words we can say it is the product of force and displacement
Formula:
Unit:
The unit of work is Joule.
So, work depends on the force applied and the displacement caused by the applied force.
If force is applied and there is no displacement, then work is 0
.
Example: Pushing a wall does no work.
Work is positive if force applied and displacement is in same direction.
Work is negative if force applied and displacement is in opposite direction.
Answer:
b. It exists in three different states at normal conditions in the Earth's atmosphere
Explanation:=
Snow, rain and water vapour can exist at normal conditions in the Earth's atmosphere.
a. is wrong. Only hydrogen and helium can escape Earth's atmosphere in significant amounts.
c. is wrong. The molecules of every substance are in motion even when it is solid.
d. is wrong. Other substances can form from a wide range of chemical processes.
e. is wrong. All substances expand when they become a gas.
Answer:
When the pressure increases to 2.35 atm, the temperature will increase to 378 K
Explanation:
Step 1: Data given
The initial pressure = 1.82 atm
The initial temperature = 293 K
The pressure will be increased to 2.35 atm
Step 2: Calculate the new temperature
P1/T1 = P2/T2
⇒with P1 = the initial pressure = 1.82 atm
⇒with T1 = the initial temperature = 293 K
⇒with P2 = the increased pressure = 2.35 atm
⇒with T2 = the new temperature = TO BE DETERMINED
1.82atm / 293 K = 2.35 atm / T2
T2 = 2.35 atm / (1.82 atm/293 K)
T2 = 2.35 / 0.0062116
T2 = 378 K
When the pressure increases to 2.35 atm, the temperature will increase to 378 K
To solve this we assume
that the gas is an ideal gas. Then, we can use the ideal gas equation which is
expressed as PV = nRT. At a constant temperature and number of moles of the gas
the product of PV is equal to some constant. At another set of condition of
temperature, the constant is still the same. Calculations are as follows:
P1V1 =P2V2
V2 = P1 V1 / P2
V2 = 153 x 3.00 / 203
<span>V2 = 2.26 L</span>
