If it takes 1 minute for 45c of charge to pass a point in an electric circuit. What is the current through the circuit

An astronaut circling the earth at an altitude of 400 km is horrified to discover that a cloud of space debris is moving in the

elena-14-01-66 [18.8K]

One of the essential concepts to solve this problem is the utilization of the equations of centripetal and gravitational force.

From them it will be possible to find the speed of the body with which the estimated time can be calculated through the kinematic equations of motion. At the same time for the calculation of this speed it is necessary to clarify that this will remain twice the ship, because as we know by relativity, when moving in the same magnitude but in the opposite direction, with respect to the ship the debris will be double speed.

By equilibrium the centrifugal force and the gravitational force are equal therefore

$F_c = F_g$

$\frac{mv^2_{orbit}}{r} = \frac{GMm}{r^2}$

Where

m = mass spacecraft

v = velocity

G = Gravitational Universal Constant

M = Mass of earth

$r \rightarrow R+h \Rightarrow$ Radius of earth and orbit

Re-arrange to find the velocity

$\frac{mv^2_{orbit}}{r} = \frac{GMm}{r^2}$

$\frac{v^2_{orbit}}{r} = \frac{GM}{r^2}$

$v^2_{orbit}=\frac{GM}{r}$

$v_{orbit} = \sqrt{\frac{GM}{r}}$

$v_{orbit} = \sqrt{\frac{GM}{R+h}}$

Replacing with our values we have

$v_{orbit} = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{6.37*10^6+0.4*10^6}}$

$v_{orbit} = 7676m/s$

From the cinematic equations of motion we have to

$t = \frac{d}{2v_{orbit}} \rightarrow$ Remember that the speed is double for the counter-direction of the trajectories.

Replacing

$t = \frac{29000m}{7676m/s}$

$t = 3.778s$

Therefore the time required is 3.778s

4 0

3 years ago

Why does the area around the equator stay about the same temperature year round?

Verdich [7]

Axial Tilt and Sun Energy

This axial tilt means that during the Earth's journey around the sun the poles receive varying amounts of sunlight. The equator, however, receives relatively consistent sunlight all year. The consistency of energy means the equator's temperature stays relatively constant all year.

3 0

4 years ago

A spaceship starting from a resting position accelerates at a constant rate of 9.8 meters per second per second. How long and ho

Verizon [17]

Accelerating at 9.8 m/s² means that every second, the speed is 9.8 m/s faster than it was a second earlier. It's not important to the problem, but this number (9.8) happens to be the acceleration of gravity on Earth.

1% of the speed of light = (300,000,000 m/s) / 100 = 3,000,000 m/s .

Starting from zero speed, moving (9.8 m/s) faster every second,
how long does it take to reach 3,000,000 m/s ?

   (3,000,000 m/s) / (9.8 m/s²) = 306,122 seconds .
   (That's 5,102 minutes.)
(That's 85 hours.)
   (That's 3.54 days.)

Speed at the beginning . . . zero .
Speed at the end . . . 3,000,000 m/s
Average speed . . . . . 1,500,000 m/s

Distance = (average speed) x (time)

   = (1,500,000 m/s) x (306,122 sec) = 4.592 x 10¹¹ meters

   = 459 million kilometers

   That's like from Earth
      to    Sun
       to    Earth
          to Sun.

4 0

3 years ago

What is the nature of force between two charges if q1+q2=0

MAXImum [283]

Answer:
The force will be attractive.

Explanation:
Since we the sum of the charges is 0 they must have opposite charges and equal magnitudes.

And Opposite charges are attaractive towards each other.

3 0

4 years ago

An action force is 50 N to the left. The reaction force must be:

igomit [66]

<h2>According to Newton's Third Law:</h2><h3>"For every action,there exists an equal and opposite reaction"</h3>

<h3>So an action force of 50 N to the left, results in a 50 N reaction force to the right.</h3>

<h2>Option A</h2>

7 0

2 years ago

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