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Answer:
783.2 N.m or Joules
Explanation:

Work done when a force F is applied to move an object by a displacement d meters
where cos(Ф) is the angle between applied force F and displacement d
Since the weightlifter is applying the force upward and the set of weight also move upward therefore, both are in same direction hence angle will be zero.
Now lets substitute the given values into the work equation:

since cos(0)=1


or

Since the unit of Force is Newton (N) and the unit of displacement is meters (m) therefore, unit of work done will be N.m
Note: 1 N.m is equivalent to 1 joule
Answer:
a) the distance between her and the wall is 13 m
b) the period of her up-and-down motion is 6.5 s
Explanation:
Given the data in the question;
wavelength λ = 26 m
velocity v = 4.0 m/s
a) How far from the wall is she?
Now, The first antinode is formed at a distance λ/2 from the wall, since the separation distance between the person and wall is;
x = λ/2
we substitute
x = 26 m / 2
x = 13 m
Therefore, the distance between her and the wall is 13 m
b) What is the period of her up-and-down motion?
we know that the relationship between frequency, wavelength and wave speed is;
v = fλ
hence, f = v/λ
we also know that frequency is expressed as the reciprocal of the time period;
f = 1/T
Hence
1/T = v/λ
solve for T
Tv = λ
T = λ/v
we substitute
T = 26 m / 4 m/s
T = 6.5 s
Therefore, the period of her up-and-down motion is 6.5 s
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