All categories

4 years ago

Consider the following chemical reaction:

Chemistry

2 answers:

VashaNatasha [74]4 years ago

7 0

Here's your solution. Hope it helps.

Viefleur [7K]4 years ago

3 0

According to the equation, the ratio of $HC\ell$ to $C\ell_2$ is $4:1$ . Then:

$\dfrac{n_{HC\ell}}{n_{C\ell_2}}=\dfrac{4}{1}\Longrightarrow\dfrac{0.268}{n_{C\ell_2}}=\dfrac{4}{1}\Longrightarrow n_{C\ell_2}=\dfrac{0.268}{4}\iff n_{C\ell_2}=0.067~mol$

Now we can calculate the mass of $C\ell_2$ formed.

$m_{C\ell_2}=n_{C\ell_2}\cdot MM_{C\ell_2}\Longrightarrow m_{C\ell_2}=0.067\cdot(2\cdot35.5)\Longrightarrow\\\\
m_{C\ell_2}=0.067\cdot71\Longrightarrow\boxed{m_{C\ell_2}=4.757~g}$

You might be interested in

By titration, it is found that 28.5 mL of 0.183 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the

maksim [4K]

Answer:

0.209M

Explanation:

M1V1=M2V2

(28.5 mL)(0.183M)=(25.0mL)(M)

M2= 0.209M

*Text me at 561-400-5105 for private tutoring if interested: I can do homework, labs, and other assignments :)

4 0

3 years ago

The maximum kinetic energy of a box sliding from the top of a ramp to the bottom is A) at the top. B) at the bottom. C) at the e

Readme [11.4K]

Kinetic energy of an object can be expressed in terms of its mass m and velocity v as:

KE = 1/2 * m* v²

Thus higher the velocity, greater will be the Kinetic energy. Now, as the box moves along a ramp from top to bottom, its velocity increases and so does the KE. Hence, kinetic energy is maximum at the bottom

Ans B) at the bottom

8 0

3 years ago

Read 2 more answers

How many moles of naoh are present in 29.0 ml of 0.290 m naoh?

Dovator [93]

29.0 mL in liters:

29.0 / 1000 => 0.029 L

n = M x V

n = 0.290 x 0.029

n = 0.00841 moles of NaOH

hope this helps!

7 0

3 years ago

(a) The mass density of a gaseous compound was found to be 1.23 kg m^−3 at 330 K and 20 kPa. What is the molar mass of the compo

Luden [163]

Answer:

The molar mass of the compound is:- 168.82 g/mol

The molar mass of the gas is:- 16.38 g/mol

Explanation:

(a)

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Also,

Moles = mass (m) / Molar mass (M)

Density (d) = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

$PM=dRt$

Given that:-

Pressure = 20 kPa = 20000 Pa

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = $\frac {1}{101325}$ P (atm)

20000 Pa = $\frac {20000}{101325}$ atm

Pressure = 0.1974 atm

Temperature = 330 K

d = 1.23 kg/m³ = 1.23 g/L

Molar mass = ?

Applying the equation as:

0.1974 atm × M = 1.23 g/L × 0.0821 L.atm/K.mol × 330 K

⇒M = 168.82 g/mol

<u>The molar mass of the compound is:- 168.82 g/mol</u>

(b)

Given that:

Pressure = 152 Torr

Temperature = 298 K

Volume = 250 cm³ = 0.25 L

Using ideal gas equation as:

$PV=nRT$

R = $62.3637\text{torr}mol^{-1}K^{-1}$

Applying the equation as:

152 Torr × 0.25 L = n × 62.3637 L.torr/K.mol × 298 K

⇒n = 0.002045 moles

Given that :

Mass of the gas = 33.5 mg = 0.0335 g

Molar mass = ?

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.002045\ moles
= \frac{0.0335\ g}{Molar\ mass}$

<u>The molar mass of the gas is:- 16.38 g/mol</u>

5 0

3 years ago

Magnesium (24.30 g) reacts with hydrogen chloride (X g) to produce hydrogen gas (2.04 g) and magnesium chloride (96.90 g). How m

makvit [3.9K]

Answer:

$74.64\ \text{g}$

Explanation:

Reactants

Magnesium = 24.3 g

Hydrogen chloride= x g

Products

Hydrogen gas = 2.04 g

Magnesium chloride = 96.9 g

As the mass of the reactions is conserved we have

Mass of reactants = Mass of products

$24.3+x=2.04+96.9\\\Rightarrow x=2.04+96.9-24.3\\\Rightarrow x=74.64\ \text{g}$

Mass of hydrogen chloride is $74.64\ \text{g}$ .

7 0

3 years ago