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Natalija [7]
3 years ago
7

When determining the standard reduction potential of a substance by using a standard hydrogen electrode as a reference, the stan

dard reduction potential will always be equal to:______.
ta. he reduction potential for the standard hydrogen electrode.
b. one-half the cell potential.
c. the overall cell potential.
d. impossible to predict.
Chemistry
1 answer:
nika2105 [10]3 years ago
4 0

Answer:

the overall cell potential

Explanation:

We must bear in mind that the standard hydrogen electrode is a reference electrode whose electrode potential has been arbitrarily set at 0 V.

The standard hydrogen electrode consists of hydrogen ion solution and hydrogen gas together with a platinum electrode.

The overall cell potential is the reduction potential of the substance being determined using the standard hydrogen electrode as a reference electrode since its electrode potential is set at zero volts.

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Karolina [17]

Answer:

11 is the coefficient for C to balance the equation

Explanation:

C₁₂H₂₂O₁₁(s)  +  H₂SO₄(aq)  +  1/2 O₂(g)   → 11C(s) + CO₂(g) + 12H₂O(g) + SO₂(g)

12 Carbons in left side   →   12 Carbons in right side

12 in sucrose → 11 in solid C + 1 in the CO₂

24 Hydrogens in left side → 24 Hydrogens in right side

22 in sucrose + 2 in sulfuric → 24 in water vapor

1 S in left side → 1 S in right side

1 S in sulfuric → 1 S in sulfur dioxide

16 O in left side → 16 O in right side

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7 0
3 years ago
What do all steroids have in common?
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The answer to this is "D" The reason it is not "C" is because some steroids are used to treat medical issues, and others are used for the purpose of repairing the muscle faster after working out such as anabolic steroid
5 0
3 years ago
An industrial synthesis of urea obtains 87.5 kg of urea upon reaction of 68.2 kg of ammonia with excess carbon dioxide. Determin
dolphi86 [110]

Answer:

The theoretical yield of urea = <u>120.35kg</u>

The percent yield for the reaction = <u>72.70%</u>

Explanation:

Lets calculate -

The given reaction is -

2NH_3(aq)+CO_2 →CH_4N_2O(aq)+H_2O (l)

Molar mass of urea CH_4N_2O= 60g/mole

Moles of NH_3 = \frac{62.8kg/mole}{17g/mole} (since Moles=\frac{mass  of  substance}{mass of one mole})

                     = 4011.76 moles

Moles of CO_2 = \frac{105kg}{44g/mole}

                = \frac{105000g}{44g/mole}

                = 2386.36 moles

Theoritically , moles of NH_3 required = double the moles of CO_2

    but , 4011.76 , the limiting reagent is NH_3

Theoritical moles of urea obtained = \frac{1 mole CH_4N_2O}{2mole NH_3}\times4011.76 mole NH_3

                                                      = 2005.88mole CH_4N_2O

Mass of 2005.88 mole of CH_4N_2O =2005.88 mole \times\frac{60g CH_4N_2O}{1mole CH_4N_2O}

                                                     = 120352.8g

                                                     120352.8g\times \frac{1kg}{1000g}

                                                     = 120.35kg

Therefore , theroritical yeild of urea = 120.35kg

Now , Percent yeild = \frac{87.5kg}{120.35kg}\times100

                                 72.70%

Thus , the percent yeild for the reaction is 72.70%

8 0
3 years ago
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Answer:

D. 12

Explanation:

The pH is a measure of the acidity of a solution. The pH indicates the concentration of hydronium ions [H3O +] present in a solution;

pH = - log [H3O+]

So

pH= - log [7.8 × 10−13 M]

finally

pH= 12

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