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brilliants [131]
3 years ago
11

How much heat is required to raise the temperature of 0.50 kg of liquid water from 15℃ to 90℃?

Chemistry
1 answer:
jolli1 [7]3 years ago
4 0
This will require 266.9k j of heat energy my explanation for this is to calculate the energy required to raise the temperature of any given substance here what you require the mass of the material,m the temperature change that occurs AT
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A type of force where objects touch each other ​
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Answer:

contact force

Explanation:

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How is freeze dried ice cream made
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4 0
3 years ago
Which is the formula for magnesium nitride?
Mekhanik [1.2K]

Explanation:

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5 0
3 years ago
Read 2 more answers
13. How many moles of sodium hydroxide are needed to neutralize 50grams of sulfuric acid?
Phoenix [80]

Answer:

1.02mole

Explanation:

The reaction equation is given as:

     2NaOH  +  H₂SO₄ →  Na₂SO₄  + 2H₂O

Given:

Mass of H₂SO₄  = 50g

Unknown:

Number of moles of NaOH = ?

Solution:

To solve this problem, we first find the number of moles of the acid given;

  Number of moles  = \frac{mass}{molar mass}

Molar mass of H₂SO₄ = 2(1) + 32 + 4(16)  = 98g/mol

Now;

   Number of moles = \frac{50}{98}   = 0.51mole

From the balanced reaction equation:

       1 mole of H₂SO₄ will be neutralized by 2 mole of NaOH

     0.51 mole of H₂SO₄ will be neutralized by 2 x 0.51  = 1.02mole of NaOH

6 0
2 years ago
Hat volume of a 0.540 M NaOH solution contains 12.5 g NaOH
amid [387]

Answer:

At 0.58 L of 0.540 M NaOH solution contain 12.5 g NaOH.

Explanation:

Given data:

At volume = ?

Mass of NaOH = 12.5 g

Molarity of solution = 0.540 M

Solution:

First of all we will calculate the number of moles of sodium hydroxide.

Number of moles = mass/molar mass

Number of moles = 12.5 g / 40 g/mol

Number of moles = 0.3125 mol

Volume of NaOH:

Molarity = number of moles / volume in L

Now we will put the values.

0.540 M = 0.3125 mol / volume in L

volume in L = 0.3125 mol / 0.540 mol/L

volume in L = 0.58 L

5 0
3 years ago
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