Answer: -
First Ionization energy IE 1 for element X = 801
Here X is told to be in the third period.
So principal quantum number n = 3 for X.
For 1st ionization energy the expression is
IE1 = 13.6 x Z ^2 / n^2
Where Z =atomic number.
Thus Z =( n^2 x IE 1 / 13.6)^(1/2)
Z = ( 3^2 x 801 / 13.6 )^ (1/2)
= 23
Number of electrons = Z = 23
Nearest noble gas = Argon
Argon atomic number = 18
Number of extra electrons = 23 – 18 = 5
a) Electronic Configuration= [Ar] 3d34s2
We know that more the value of atomic radii, lower the force of attraction on the electrons by the nucleus and thus lower the first ionization energy.
So more the first ionization energy, less is the atomic radius.
X has more IE1 than Y.
b) So the atomic radius of X is lesser than that of Y.
c) After the first ionization, the atom is no longer electrically neutral. There is an extra proton in the atom. Due to this the remaining electrons are more strongly pulled inside than before ionization. Hence after ionization, the radii of Y decreases.
Answer:
Yeasts reproduce asexually by a process called budding (see Figure 8.2. 1 and Figure 8.2. 6). A bud is formed on the outer surface of the parent cell as the nucleus divides.
Explanation:
Answer:
C. by its chemical Symbol
Hope this helps!
The density of properties will not increase by changing the amount of materials, but only will change if temperature changes because it is the weight <em>per cubic centimeter</em>. For example if you have 20000 grams of gold and its volume is 1040 cubic centimeters, but you also have 550 grams of gold which has a volume of 28.5 cubic centimeters the calculations prove it;
20,000/1040= 19.2 grams per cubic centimeter
as well as 550/28.5= 19.2 grams per cubic centimeter.
