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Lemur [1.5K]
3 years ago
10

My teacher is grading this soon can someone help me ASAP!

Chemistry
1 answer:
Stolb23 [73]3 years ago
3 0

10. You demonstrated the difference in density of the two objects. It is a physical property.

11. First calculate the density for all of them: density = mass/volume

Density:

A. 5/6 g/ml

B. 10/9 g/ml

C. 15/16 g/ml

D. 20/10 g/ml

If the density of the substance is higher than the density of the substance it is put in, then it will sink. So substances B and D will sink in water, as their densities are higher than 1 g/ml.

12. Ammonia weighs less than water does-- for example, the weight of 8 gallons of ammonia will be equivalent to the weight of 5 gallons of water.

Hope this helped!

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What is the mass of 1.71 ✕ 1023 molecules of h2so4?
Anuta_ua [19.1K]
The equation for calculating a mass is as follows:

m=n×M

Molar mass (M) we can determine from Ar that can read in a periodical table, and a number of moles we can calculate from the available date for N:

n(H2SO4)=N/NA

n(H2SO4)= 1.7×10²³ / 6 × 10²³

n(H2SO4)= 0.3 mole

Now we can calculate a mass of H2SO4:

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7 0
3 years ago
In the presence of sulfuric acid, this alcohol is dehydrated to form an alkene through an E1 mechanism. In the box, draw the maj
Sophie [7]

Answer:

figure is attached

Explanation:

When we treat alcohol with H₂SO₄ we get elimination as the major product.

As we can see in the given reaction that in step 1 the lone pair of electrons of oxygen attached to the alcohol make a bond with the hydrogen of H₂SO₄.

In the 2nd step H₂O gets detached from the parent ring which generated a positive charge on the ring.

In the 3rd step elimination of hydrogen from the carbon next to the carbonium carbon results into formation of an alkene.

5 0
3 years ago
Calculate the slope of each line using the points given. (25.6cm³ , 28.16g), (17.3cm³, 19.03g)
fiasKO [112]

Answer:

1.1

Explanation:

The slope of a line can be calculated using the values of the x and y corrdinates. The equation is given as;

M = ΔY /  ΔX = Y2 - Y1 / X2 - X1

From the points;

(25.6cm³ , 28.16g) - (X1, Y1)

(17.3cm³, 19.03g) - (X2,  Y2)

Inserting the values into the equation;

M = 19.03 - 28.16 /  17.3 - 25.6

M = -9.13 / -8.3 = 1.1

3 0
2 years ago
A student heats a sample of Copper (II) sulfate in a crucible and records the data shown in the table. What is the complete form
liberstina [14]

Explanation:

Copper (II) sulfate is usually present as a hydrous state, which is of the form CuSO4 * nH2O, where n is a whole number.

Mass of sample (CuSO4 * nH2O)

= 152.00g - 128.10g = 23.90g.

Mass of water loss during heating

= 152.00g - 147.60g = 4.40g.

Molar mass of H2O = 18g/mol

Moles of H2O in sample

= 4.40g / (18g/mol) = 0.244mol.

Mass of anhydrous sample (CuSO4)

= 23.90g - 4.40g = 19.50g

Molar mass of CuSO4 = 159.61g/mol

Moles of CuSO4 in sample

= 19.50g / (159.61g/mol) = 0.122mol.

Since mole ratio of CuSO4 to H2O

= 0.122mol : 0.244mol = 1:2, n = 2.

Hence we have CuSO4 * 2H2O.

6 0
3 years ago
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