Steps 1 and 3 are correct rate
Answer:
6.05g
Explanation:
The reaction is given as;
Ethane + oxygen --> Carbon dioxide + water
2C2H6 + 7O2 --> 4CO2 + 6H2O
From the reaction above;
2 mol of ethane reacts with 7 mol of oxygen.
To proceed, we have to obtain the limiting reagent,
2,71g of ethane;
Number of moles = Mass / molar mass = 2.71 / 30 = 0.0903 mol
3.8g of oxygen;
Number of moles = Mass / molar mass = 3.8 / 16 = 0.2375 mol
If 0.0903 moles of ethane was used, it would require;
2 = 7
0.0903 = x
x = 0.31605 mol of oxygen needed
This means that oxygen is our limiting reagent.
From the reaction,
7 mol of oxygen yields 4 mol of carbon dioxide
0.2375 yields x?
7 = 4
0.2375 = x
x = 0.1357
Mass = Number of moles * Molar mass = 0.1357 * 44 = 6.05g
Answer: chemical property
Explanation: This is a chemical property because it was combined with carbon, another molecule acting like an element. The answer to the question is chemical property. Hope this helps!
For #3 the answer is B, for #4 the answer is F, and for #5 the answer is B.
Answer:
The correct answer is option E.
Explanation:
Mass of ferric oxide decomposed = 57.0 g
Moles of ferric oxide decomposed = 
According to reaction, 2 moles ferric oxide on combustion gives 824.2 kJ of heat.
Then heat given by on decomposition of 0.35625 mol of ferric oxide will be:
So, on decomposition of 57.0 grams of ferric oxide 147 kilo Joules of heat was released.
