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Ne4ueva [31]
3 years ago
6

Write -2i + (9 − 3i) − (6 − 10i) as a complex number in standard form.

Mathematics
2 answers:
vovikov84 [41]3 years ago
8 0

Answer:

5i+3

Step-by-step explanation:

Given the expression

-2i + (9 − 3i) − (6 − 10i)

Where i² = -1 (complex number rule)

Therefore,

-2i + 9-3i-6+10i

Collecting like terms gives

5i+3

Vika [28.1K]3 years ago
6 0
<span>-2i + (9 − 3i) − (6 − 10i)
-2i - 3i + 10i + 9 - 6
5i + 3
3 + 5i</span>
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Answer:

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Step-by-step explanation:

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Factor the following expression. 36y - 12
Over [174]

Hey there!


36y - 12


FIRST LOOK AT THE GCF (Greatest Common Factor)


36y: 1, 2, 3, 4, 6, 9, 12, 18, 36, and y


12: 1, 2, 3, 4, 6, and 12


GCF: 12


So, 12 would most likely be number before you make your parentheses


12(?y - 1)


The numbers in your original equation both share 3 & -1


So, therefore the factor form of your equation should be: 12(3y - 1)


Answer: 12(3y - 1)


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2(h-8)-h=h-16 what is the solution
BartSMP [9]
STEP-BY-STEP SOLUTION:

To solve this equation, first make ( h ) the subject and then simplify as much as possible as displayed below:

2 ( h - 8 ) - h = h - 16

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4 0
3 years ago
F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa
DerKrebs [107]

a. Parameterize C by

\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath

with 0\le t\le1.

b/c. The line integral of \vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath over C is

\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt

=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt

=\displaystyle10\int_0^1\mathrm dt=\boxed{10}

d. Notice that we can write the line integral as

\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)

By Green's theorem, the line integral is equivalent to

\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy

where D is the triangle bounded by C, and this integral is simply twice the area of D. D is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

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3 years ago
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Step-by-step explanation:

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