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Ne4ueva [31]
2 years ago
6

Write -2i + (9 − 3i) − (6 − 10i) as a complex number in standard form.

Mathematics
2 answers:
vovikov84 [41]2 years ago
8 0

Answer:

5i+3

Step-by-step explanation:

Given the expression

-2i + (9 − 3i) − (6 − 10i)

Where i² = -1 (complex number rule)

Therefore,

-2i + 9-3i-6+10i

Collecting like terms gives

5i+3

Vika [28.1K]2 years ago
6 0
<span>-2i + (9 − 3i) − (6 − 10i)
-2i - 3i + 10i + 9 - 6
5i + 3
3 + 5i</span>
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6 0
2 years ago
Hey! Can someone do this real quick? 20 points!!!
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Answer:

i think about 80 cm or 100cm

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3 years ago
Read 2 more answers
I don't know if this is right... please someone help mee
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For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

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this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
2 years ago
2. <br> Find the area of the region bounded by the graphs of y = -x2 + 3x + 4 and y = 4. (5 points)
Kipish [7]

Answer:

4.5 sq. units

Step-by-step explanation:

area = -⅓x³+3/2 x² ] 0 to 3

= -⅓(3)³+ 3/2 (3)² -0

= -9 + 27/2

= -9 + 13.5

= 4.5 sq. units

8 0
3 years ago
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