This is the equation for elastic potential energy, where U is potential energy, x is the displacement of the end of the spring, and k is the spring constant.
<span> U = (1/2)kx^2
</span><span> U = (1/2)(5.3)(3.62-2.60)^2
</span> U = <span>
<span>2.75706 </span></span>J
An object moving with constant velocity
It's mostly used in CHEMICAL PROCESSES.
Answer:
0.37 m
Explanation:
The angular frequency, ω, of a loaded spring is related to the period, T, by

The maximum velocity of the oscillation occurs at the equilibrium point and is given by

A is the amplitude or maximum displacement from the equilibrium.

From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,

To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation

is the final velocity,
is the initial velocity (same as v above), a is acceleration of gravity and h is the height.

