Question

A simple pendulum on the surface of Earth is found to undergo 15.0 complete small‑amplitude oscillations in 8.75 s. Find the pendulum's length.

Answer 1

Answer:

Length of the Pendulum is 14.4 cm

Explanation:

Time period of simple pendulum is given by

$T=2\pi \sqrt{\frac{L}{g} }$

time taken for one oscillation is

$T=\frac{time taken}{oscillations} \\T=\frac{8.75}{15} \\T=0.583 s$

Pendulum length on the earth surface is

$L=\frac{T^2g}{4\pi^2 }\\L=\frac{0.583\times 9.8}{4\pi^2 } \\L=0.144 m$

Length of the Pendulum is 14.4 cm