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Monica [59]
4 years ago
8

A simple pendulum on the surface of Earth is found to undergo 15.0 complete small‑amplitude oscillations in 8.75 s. Find the pen

dulum's length.
Physics
1 answer:
FinnZ [79.3K]4 years ago
6 0

Answer:

Length of the Pendulum is 14.4 cm

Explanation:

Time period of simple pendulum is given by

T=2\pi \sqrt{\frac{L}{g} } \\

time taken for one oscillation is

T=\frac{time taken}{oscillations} \\T=\frac{8.75}{15} \\T=0.583 s

Pendulum length on the earth surface is

L=\frac{T^2g}{4\pi^2 }\\L=\frac{0.583\times 9.8}{4\pi^2 } \\L=0.144 m

Length of the Pendulum is 14.4 cm

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S_A_V [24]

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10.2 Watt

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Change in magnetic field is given as

ΔB = B - B₀ = - 0.40 - 0.40 = - 0.80 T

t  = time taken for the magnetic field to change = 2.0 s

Induced emf is given as

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E = \frac{- (160) (0.20) (- 0.80)}{2}

E = 12.8 volts

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Power is given as

P = \frac{E^{2}}{R}

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6 0
3 years ago
The accepted value for the density of iron is 7.87 g/cm3. a student records the mass of a 20.00 cm3 block of iron as 153.8 grams
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Therefore a is the correct answer.
6 0
3 years ago
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