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marin [14]
3 years ago
11

Where does every piece of matter begin?

Physics
1 answer:
Margarita [4]3 years ago
6 0
Every piece of matter begins “Out of this world”
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The circumference of an orbit for a toy on a string is 18 m and the centripetal force is 12 N. Does the centripetal force do any
Snezhnost [94]

Answer:

Work done is 0.

Explanation:

Given that,

The circumference of an orbit for a toy on a string is 18 m, r = 18 m

Centripetal force, F = 12 N

In the circular path, the centripetal force is always perpendicular to the motion of the object. Thus it makes an angle of 90 degrees with the force and displacement. Hence, we can say that the centripetal force does not do any work on the toy when it follows its orbit for one cycle.

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3 years ago
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3 years ago
In which of the fire plume structure zones do the gases accelerate upward?
I am Lyosha [343]
The zone that gases always accelerate upward is the Luminous flame zone. The fire plume is the column of hot gases, flames and smoke rising above a fire. Gases accelerate upward toward the always luminous flame zone. The luminous flame height is the distance between the base of a flame and the point at which the plume is luminous half the time and transparent half the time.
3 0
3 years ago
A Transformer has a primary coil with 650 turns if the output voltage is 500 volts and an input voltage of 200 volts how many te
maxonik [38]

Answer:

1625

Explanation:

Ns/Np = Vs/Vp

Ns / 650 = 500/200

Ns = 2.5 x 650

Ns = 1625

6 0
3 years ago
Consider a double slit experiment in the air. The wavelength of light is 500nm light, the screen is 1m away and two adjacent bri
Bess [88]

Answer: 0.75\ cm

Explanation:

Given

Wavelength of light \lambda=500\ nm

Screen is D=1\ m away

Distance between two adjacent bright fringe is \Delta y=\dfrac{\lambda D}{d}

When same experiment done in water, wavelength reduce to \dfrac{\lambda }{\mu}

So, the distance between the two adjacent bright fringe is \Delta y'=\dfrac{\lambda D}{\mu d}

Keeping other factor same, distance becomes

\Rightarrow \dfrac{1}{\frac{4}{3}}=\dfrac{3}{4}\quad \text{Refractive index of water is }\dfrac{4}{3}\\\\\Rightarrow 0.75\ cm

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3 years ago
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