The speed of the vehicle after the push is 2.7 m/s.
<h3>What is velocity?</h3>
velocity is the rate of change of displacement.
To calculate the velocity of the vehicle, we use the formula below.
Formula:
- v = √[2(W-W')/m]............... Equation 1
Where:
- W = work done by the pusher
- W' = Work done by friction
- m = mass of the car
From the question,
Given:
- W = 6500 J
- W' = 2000 J
- m = 1200 kg
Substitute these values into equation 1
- v = √[2(6500-2000)/1200]
- v = √(7.5)
- v = 2.7 m/s
Hence, the speed of the vehicle after the push is 2.7 m/s.
Learn more about velocity here:
#SPJ1
Answer:
it has 3 electrons. brainliest please
Answer:
Explanation:
Given
speed of Electron ![u=2\times 10^7\ m/s](https://tex.z-dn.net/?f=u%3D2%5Ctimes%2010%5E7%5C%20m%2Fs)
final speed of Electron ![v=4\times 10^7\ m/s](https://tex.z-dn.net/?f=v%3D4%5Ctimes%2010%5E7%5C%20m%2Fs)
distance traveled ![d=1.2\ cm](https://tex.z-dn.net/?f=d%3D1.2%5C%20cm)
using equation of motion
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
where v=Final velocity
u=initial velocity
a=acceleration
s=displacement
![(4\times 10^7)^2-(2\times 10^7)^2=2\times a\times 1.2\times 10^{-2}](https://tex.z-dn.net/?f=%284%5Ctimes%2010%5E7%29%5E2-%282%5Ctimes%2010%5E7%29%5E2%3D2%5Ctimes%20a%5Ctimes%201.2%5Ctimes%2010%5E%7B-2%7D)
![a=5\times 10^{16}\ m/s^2](https://tex.z-dn.net/?f=a%3D5%5Ctimes%2010%5E%7B16%7D%5C%20m%2Fs%5E2)
acceleration is given by ![a=\frac{qE}{m}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BqE%7D%7Bm%7D)
where q=charge of electron
m=mass of electron
E=electric Field strength
![5\times 10^{16}=\frac{1.6\times 10^{-19}\cdot E}{9.1\times 10^{-31}}](https://tex.z-dn.net/?f=5%5Ctimes%2010%5E%7B16%7D%3D%5Cfrac%7B1.6%5Ctimes%2010%5E%7B-19%7D%5Ccdot%20E%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%7D)
Answer:
The speed of the man is 4.54 m/s.
Explanation:
Given that,
Mass of man=8100 g
Mass of stone = 79 g
Speed = 4.5 m/s
We need to calculate the speed of the man
Using momentum of conservation
![(m_{1}+m_{2})V=m_{1}v_{1}+m_{2}v_{2}](https://tex.z-dn.net/?f=%28m_%7B1%7D%2Bm_%7B2%7D%29V%3Dm_%7B1%7Dv_%7B1%7D%2Bm_%7B2%7Dv_%7B2%7D)
Where,
=mass of man
=mass of stone
=velocity of man
=velocity of stone
Put the value in the equation
As the stone is away from the man
So, the speed of stone is zero
![8179\times4.5=8100\times v+0](https://tex.z-dn.net/?f=8179%5Ctimes4.5%3D8100%5Ctimes%20v%2B0)
![v=\dfrac{8179\times4.5}{8100}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B8179%5Ctimes4.5%7D%7B8100%7D)
![v = 4.54\ m/s](https://tex.z-dn.net/?f=v%20%3D%204.54%5C%20m%2Fs)
Hence, The speed of the man is 4.54 m/s.