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2 years ago

If Vx= 9.5 units and Vy= -6.4 units, determine the magnitude of V

Physics

1 answer:

valkas [14]2 years ago

5 0

Answer:

The magnitude of the velocity is approximately 11.45 units

Explanation:

Since they give us the x and y components of the vector velocity, we can find its magnitude via the Pythagorean theorem:

$|v|=\sqrt{9.5^2+(-6.4)^2} \approx 11.45$

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Create a file "parts_inv.dat" that stores on each line a part number, cost, and quantity in inventory, in the following format:1

andriy [413]

Answer:

%Open the file.

fID = fopen('parts_inv.dat');

%Read from the file.

data = fscanf(fID,'%d\t%f\t%d',[3,inf]);

%Close

fclose(fID);

%Restore the data.

data = data';

%Get the size

[rs, cs] = size(data);

%Set value.

invCost = 0;

%Loop

for rw = 1 : rs

%Find cost

invCost = invCost + (data(rw, 2) * data(rw, 3));

%Loop end

end

%Display the cost.

fprintf('Total cost: %4.2f\n\n', invCost);

Explanation:

7 0

3 years ago

How do you verify scientific hypothesis?

sergeinik [125]

They verify scientific hypothesis by doing experiments do prove what their theory was.

3 0

3 years ago

A ball on an extremely low-friction, tilted surface will slide downhill without rotating. If the surface is rough, however, the

spayn [35]

It will go left or right

6 0

2 years ago

A bucket that has a mass of 20 kg when filled with sand needs to be lifted to the top of a 15 meter tall building. You have a ro

prohojiy [21]

Answer:

work done lifting the bucket (sand and rope) to the top of the building,

W=67.46 Nm

Explanation:

in this question we have given

mass of bucket=20kg

mass of rope= $.2\frac{kg}{m}$

height of building= 15 meter

We have to find the work done lifting the bucket (sand and rope) to the building =work done in lifting the rope + work done in lifting the sand

work done in lifting the rope is given as, $W_{1}=Force \times displacement$

= $\int\limits^{15}_0 {.2x} \, dx$ ..............(1)

= $.1\times 15^2$

=22.5 Nm

work done in lifting the sand is given as, $W_{2}=Force \times displacement$

$W_{2}=\int\limits^{15}_0 F \, dx$ .................(2)

Here,

F=mx+c

here,

c=20-18

c=2

m= $\frac{20-18}{15-0}$

m=.133

Therefore,

$F=.133x+2$

Put value of F in equation 2

$W_{2}=\int\limits^{15}_0 (.133x+2) \, dx$

$W_{2}=.133 \times 112.5+2\times15\\W_{2}=14.96+30\\W_{2}=44.96 Nm$

Therefore,

work done lifting the bucket (sand and rope) to the top of the building, $W=W_{1}+W_{2}$

W=22.5 Nm+44.96 Nm

W=67.46 Nm

4 0

3 years ago

A radio technician measures the frequency of an AM radio transmitter. The frequency is . What is the frequency in megahertz? Wri

sukhopar [10]

Complete Question

A radio technician measures the frequency of an AM radio transmitter. The frequency is 14603 kHz . What is the frequency in megahertz? Write your answer as a decimal.

Answer:

The value is $x = 14.6 \ MHz$

Explanation:

From the question we are told that

The frequency is $f = 14603 \ kHz = 14603 *1000 = 14603000 \ Hz$

Generally

$1 Hz \to 1.0 *10^{-6} \ MHz$

$14603000 \ Hz \to x MHz$

=> $x = \frac{14603000 * 1.0*10^{-6}}{1 }$

=> $x = 14.6 \ MHz$

8 0

2 years ago