Multicellular organisms, as the name implies, have many types of cells, while unicellular organisms contain just one cell each. Both kinds of organisms reproduce through meiosis or mitosis. Multicellular organisms generally form the higher tiers in the web of life. These living beings, including plants and animals, have a more complex internal layout than unicellular creatures. They rely on specialized cells and cell departments for carrying out specific tasks, such as breaking down food, sending electrical messages and other duties necessary for supporting life. This distinction, called cell differentiation, lets multicellular organisms engage in more complex physical and cognitive tasks than unicellular organisms.In addition to having specialized cells, multicellular organisms have separate organ systems to perform specific tasks. These systems, such as the cardiovascular, digestive and respiratory systems, perform life processes necessary for survival. Digestive systems, for instance, deliver nutrients and energy to organs in the digestive tract, letting them process and digest food. These organ systems also facilitate communications between different types of systems, such as the circulatory and nervous systems.
Answer:
96.7 s
Explanation:
Time of flight in projectile can be calculated thus:
T = 2 × u × sin ϴ/ g
Where;
T = time of flight (s)
u = initial velocity (m/s)
ϴ = Angle of projectile (°)
g = acceleration due to gravity (9.8m/s²)
Based on the provided information; u = 670m/s, ϴ = 45°
Hence, using T = 2.u.sin ϴ/ g
T = 2 × 670 × sin 45° ÷ 9.8
T = 1340 × 0.7071 ÷ 9.8
T = 947.52 ÷ 9.8
T = 96.68
T = 96.7s
Answer:
28.8 cm
Explanation:
Magnification in a microscope is:
M = Mo * Me
Where
Mo: magnification of the objective,
Me: Magnification of the eyepiece.
The magnification of the objective if:
Me = npd/fe
Where:
npd: near point distance
fe: focal length of the eyepiece
The magnification of the objective:
Mo = d/fo
Where
d: the distance between lenses
fo: focal length of the objective
Then
M = npd/fe * d/fo
d = M * fe * fo / npd
d = 12 * 5 * 12 / 25 = 28.8 cm
Answer:
*he force to climb a plane inlcinado with constant velicad is equal to the cosine of the weight of the body
*he force to climb a plane inlcinado with constant velicad is equal to the cosine of the weight of the body
Explanation:
When a car is going up an inclined plane with constant speed, we can solve the problem using the translational equilibrium equation
Let's locate one axis parallel to the plane and the other perpendicular
F - W x = 0
F = W cos tea
therefore wes ee that the force to climb a plane inlcinado with constant velicad is equal to the cosine of the weight of the body
Work is defined by
W = F. l
in this case the force and displacement are constant
W = F L
where L is the length of the plane
W = mgL cos tes
we see that the work is equal to the cosine of the force times the distance on the plane