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marishachu [46]
3 years ago
8

Along some shorelines, incoming waves cause the water to simply rise and fall rather that form a surf zone. What does this tell

you about these shorlines?
Physics
1 answer:
NARA [144]3 years ago
5 0

Answer:

Explained

Explanation:

Along some shorelines, incoming waves cause the water to simply rise and fall and not form surfs because of the steepness of the shorelines. Long period waves wont form surfs at steep shores because of the breaking and unstability of waves. Wave breaks at the shallow waters. The breaking of the waves depends upon H/L ratio.

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Why are airplanes filled with pressurized air and oxygen
zimovet [89]

Answer:

Airplane cabins are pressurized because as the airplane climbs higher in altitude, the air becomes very thin, this pressurization ensures that there is still enough breathable oxygen in the cabin to prevent everyone from suffering the effects of hypoxia and passing out.

plz give brainlist :'D

7 0
3 years ago
When describing the scientific evidence, what is the meaning of the word repeatable?
muminat
Hello there, 
The word 'repeatable' means, the scientific experiment is repeated in the same way, with the same methods and analysis.

Hope this helps :))

~Top
7 0
3 years ago
In a car how does an air bag minimize the force acting on a person during a collision
Klio2033 [76]
It decreases the momentum in the car.
4 0
3 years ago
Read 2 more answers
6. A dumb, bored child wants to see what will happen if they jump off the top of their shed with an umbrella. As you can guess,
ale4655 [162]

Answer:

All i kno is that that kid ain't gonna be ok

Explanation:

if u tell me how to do it ill do it

5 0
3 years ago
Two charges, each of 2.9 microC are placed at two corners of a square 50cm on a side, If the charges are on one side of the squa
anyanavicka [17]

Answer:

The magnitude of the electric field and direction of electric field are 146.03\times10^{3}\ N/C and 75.36°.

Explanation:

Given that,

First charge q_{1}= 2.9\mu C

Second chargeq_{2}= 2.9\mu C

Distance between two corners r= 50 cm

We need to calculate the electric field due to other charges at one corner

For E₁

Using formula of electric field

E_{1}=\dfrac{kq}{r'^2}

Put the value into the formula

E_{1}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\sqrt{2}\times10^{-2})^2}

E_{1}=52200=52.2\times10^{3}\ N/C

For E₂,

Using formula of electric field

E_{1}=\dfrac{kq}{r^2}

Put the value into the formula

E_{2}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\times10^{-2})^2}

E_{2}=104400=104.4\times10^{3}\ N/C

We need to calculate the horizontal electric field

E_{x}=E_{1}\cos\theta

E_{x}=52.2\times10^{3}\times\cos45

E_{x}=36910.97=36.9\times10^{3}\ N/C

We need to calculate the vertical electric field

E_{y}=E_{2}+E_{1}\sin\theta

E_{y}=104.4\times10^{3}+52.2\times10^{3}\sin45

E_{y}=141310.97=141.3\times10^{3}\ N/C

We need to calculate the net electric field

E_{net}=\sqrt{E_{x}^2+E_{y}^2}

Put the value into the formula

E_{net}=\sqrt{(36.9\times10^{3})^2+(141.3\times10^{3})^2}

E_{net}=146038.69\ N/C

E_{net}=146.03\times10^{3}\ N/C

We need to calculate the direction of electric field

Using formula of direction

\tan\theta=\dfrac{141.3\times10^{3}}{36.9\times10^{3}}

\theta=\tan^{-1}(\dfrac{141.3\times10^{3}}{36.9\times10^{3}})

\theta=75.36^{\circ}

Hence, The magnitude of the electric field and direction of electric field are 146.03\times10^{3}\ N/C and 75.36°.

4 0
3 years ago
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