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marishachu [46]
2 years ago
8

Along some shorelines, incoming waves cause the water to simply rise and fall rather that form a surf zone. What does this tell

you about these shorlines?
Physics
1 answer:
NARA [144]2 years ago
5 0

Answer:

Explained

Explanation:

Along some shorelines, incoming waves cause the water to simply rise and fall and not form surfs because of the steepness of the shorelines. Long period waves wont form surfs at steep shores because of the breaking and unstability of waves. Wave breaks at the shallow waters. The breaking of the waves depends upon H/L ratio.

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A bicycle rider travels 50.0 Km in 2.5 hours. What is the cyclist's average speed?
vekshin1
<span>If you divide the numbers you will get on average of 20km</span>
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12)A black body is heated from 27°C to 127° C. The ratio of their energies of radiations emitted will be
Nat2105 [25]

Answer:

81:256.

Explanation:

Let T denote the absolute temperature of this object.

Calculate the value of T before and after heating:

T(\text{before}) = 27 + 273 = 300\; \rm K.

T(\text{after}) = 127 + 273 = 400\; \rm K.

By the Stefan-Boltzmann Law, the energy that this object emits (over all frequencies) would be proportional to T^4.

Ratio between the absolute temperature of this object before and after heating:

\displaystyle \frac{T(\text{before})}{T(\text{after})} = \frac{3}{4}.

Therefore, by the Stefan-Boltzmann Law, the ratio between the energy that this object emits before and after heating would be:

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2 years ago
A race car has a centripetal acceleration of 13.33 m/s^2 as it goes around a curve. if the curve is a circle with a radius 30 m
anzhelika [568]

Answer:

The speed of the car, v = 19.997 m/s

Explanation:

Given,

The centripetal acceleration of the car, a = 13.33 m/s²

The radius of the curve, r = 30 m

The centripetal force acting on the car is given by the formula

                                   F = mv²/r

Where    v²/r is the acceleration component of the force

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Substituting the values in the above equation

                                        13.33 = v²/30

                                         v² = 13.33 x 30

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Hence, the speed of the car, v = 19.997 m/s

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Answer:

6.667 m/s

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